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Thanks again broThe two equations are:
CH4 + 2O2 --> CO2 + 2H2O
CH4 + 3/2O2 --> CO + 2H2O
multiply equation 1 by 99 and add to equation 2
99CH4 + 198O2 --> 99CO2 + 198H2O
CH4 + 3/2O2 --> CO + 2H2O
---------------------------------------------------------------------------------------- add
100CH4 + 199(1/2)O2 --> 99CO2 + CO + 200H2O
So, burning 100 moles needs 199(1/2) moles of oxygen
Therefore burning y moles needs 2y - y/200
or expressed as a decimal fraction:
2y - (0.01/2)y
i.e. answer A




