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For the practical paper, if our titre volumes are each with a difference of 0.1 with the previous, which one to include for our average volume. lyk if we have 20.4, 20.2 and 20.3 cm^3?
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Take any combination eg. 20.4 and 20.3 or 20.3 and 20.2. But the best way is to add all three and divide by 3.For the practical paper, if our titre volumes are each with a difference of 0.1 with the previous, which one to include for our average volume. lyk if we have 20.4, 20.2 and 20.3 cm^3?
Take any combination eg. 20.4 and 20.3 or 20.3 and 20.2. But the best way is to add all three and divide by 3.
its an epic,classic old movie and a block-buster hit -______-xcuse me oldfashionedgirl cud u change your profile pic please . tnx . it is very disturbing .
BESTEST.MOVIE.EVER.its an epic,classic old movie and a block-buster hit -______-
ur the first person that i've heard call ANYTHING related to this movie 'disturbing'
Don't worry. This type of question will never come out again. Trust me.an sum1 plzzz help in these questionss....i dont get how electrode potentials increases or decreases when u increase conc of of the reactants..these are the papers.q3 of oct/2010/41 and q5c of oct/2010/43
its an epic,classic old movie and a block-buster hit -______-
ur the first person that i've heard call ANYTHING related to this movie 'disturbing'
I didnt check the link but basically if an alkene has two hydrogens on one end and two alkyl groups on the other, when hot conc KMnO4 is added, the double bond breaks, the side with the two alkyl groups turns into a ketone .. and the side with the two hydrogen groups gets oxidised into CO2 and H2Opls some one tell me at the end of this page there is a question in this summary ....... related to this:saudha said: ↑how do u get a ketone and a carbon dioxide in addition to 2 methyl propane...with hot concentrated KMNO4Amy farvin said: ↑i too dont get it,to explain u.. if anyone knowz plz help us...
Can someone please explain to me the shifting of the equilibrium to left or right? :/
I am so confused about it.
Do we mean the page wala left or right or the actual left or right
and is the product side wala arrow shifting to the right
Someone pleeeeeeease help!!! :'(
eeee da products are on ur ryt syd in an equation
eg: 2Na+ Cl2 ---> 2NaCl
NaCl is da product formed here and Na and Cl are da reactants. for pressure, count da number of moles 2 know where da equilibrium shifts.here Na is 2 and 1 of Cl so total number of moles here are 3.and da products moles are just 2 so if pressure increases, equilibrium shifts 2 NaCl ie right syd cz there r less nmbr of moles there.
same goes for concentration,if conc of NaCl is increased equ. wil shift 2 da left syd ie Na + Cl (reactants) syd.
for temperature its easier to learn just 1 variable lyk if rctn is exo,increacing temperature shifts equ. 2 da reactnats syd... if its endo, increasing temp shifts equ 2 da products syd and vice versa for decreasing temp
hope u understandif dont always welcum 2 ask again
no i dont think theres dis sort of explanation for dis...we just need 2 learn which syd is favoured by increasing or decreasing da temperature...btw i edited my post for concentration..plz chckOmg thankyoooou!!
that helped a lot!! :')
for temperature its easier to learn just 1 variable lyk if rctn is exo,increacing temperature shifts equ. 2 da reactnats syd... if its endo, increasing temp shifts equ 2 da products syd and vice versa for decreasing temp
^^ could you please tell me why though? isnt exothermic bond formaton? so then why does it shft to the reactants side :/
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