Lets Get Started

[asadalam]

How much physics have u covered ...

Upto kinematics now.

 

[funky brat]

Pahlay hee ho

MAIN NERD NAHI HUN. -.-

 

[MarcoReus]

MAIN NERD NAHI HUN. -.-

That's what every nerd says.

 

[F.Z.M. 7]

MAIN NERD NAHI HUN. -.-

Prove it

 

[exploded diper]

can anyone explain the null method

 

[funky brat]

Prove it

I don't even need to prove.
You better prove that I'm a nerd.

 

[funky brat]

That's what every nerd says.

Whatever pleases you and FZM.

 

[F.Z.M. 7]

I don't even need to prove.
You better prove that I'm a nerd.

Aint nobody got time for that

 

[exploded diper]

hey do you guys post questions on doubts thread

 

[exploded diper]

f(x) = 2x^2 - 12x + 13
f (x) = 2(x-3)^2 -5
for 0=< x =< A
state the value of A for which the graph of y=f(x) has a line of symmetry

 

[exploded diper]

Concepts mostly..i cant pinpoint it but im struggling

i wonder when you are gona change your signature, if ever

 

[asadalam]

i wonder when you are gona change your signature, if ever

If it aint broke,dont fix it

 

[exploded diper]

If it aint broke,dont fix it

Dude it's pretty broke....

 

[exploded diper]

f(x) = 2x^2 - 12x + 13
f (x) = 2(x-3)^2 -5
for 0=< x =< A
state the value of A for which the graph of y=f(x) has a line of symmetry

answer me

 

[asadalam]

Dude it's pretty broke....

Not for me.

 

[M.Omar]

f(x) = 2x^2 - 12x + 13
f (x) = 2(x-3)^2 -5
for 0=< x =< A
state the value of A for which the graph of y=f(x) has a line of symmetry

6

 

[exploded diper]

6

show me the working man

 

[exploded diper]

hey did you guys buy biological sciences ( the big red book)

 

[M.Omar]

show me the working man

putting the value of x from the lowest limit of range
0<=x<=A ,we get
2(0-3)^2-5=13 ...now we know as x increases frm 0 to greater values the value of fx decreases till the point it reaches min point at x=3 after wards it increases..now we know tht this graph will have a "U" shape for this U shape to be symmetrical abt a line we need to define a limit for x such tht it will produce the same max value within the range as before...i.e before the max value within 0<=x<=A was at 0 when fx=13 now the upper limit i.e A shud have an x value such tht it will produce the same max value tht is 13... we can find it thru this eq ...tht is
2(x-3)^2 -5=13 ...(x-3)^2=9 ,so x-3=+/- (3), x=0 or x=6 since we already have x=0 in one of the 2 limits of our range ,it means tht 6 is the other value in the limits of our range and thus A=6

 

[funky brat]

hey did you guys buy biological sciences ( the big red book)

Yeah, Ima buy it.