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Mathematics: Post your doubts here!

Mustehssun Iqbal

Mustehssun Iqbal

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usmiunique said:
draw up a possibility diagram.. it will be like this
Since the sum of the scores is required,

_|1 2 3 4 5 6
1 |2 3 4 5 6 7
2|3 4 5 6 7 8
3|4 5 6 7 8 9
4|5 6 7 8 9 10
5|6 7 8 9 10 11
6|7 8 9 10 11 12
from the diagram, it can be seen that there are 15 outcomes greater than or equal to 8 so, the probablity is 15/36
hope u understood!
Click to expand...
this thing kind of flew over my head, but thanks for the effort :D
 
usmiunique

usmiunique

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Mustehssun Iqbal said:
this thing kind of flew over my head, but thanks for the effort :D
Click to expand...
U have 2 dices that u throw right!
Both dice dice can have any value from 1 to 6.. The score is the sum of the numbers on the two dices!
In that diagram, we take all possible values like if we assume the score in the first dice is 1, then the corresponding score on The second dice can be any number from 1 to 6.. Just like that for 2,3,4,5 and 6 is done. Both numbed are added together to give the score and hence ALL possible scores are noted in that table!
 
Mustehssun Iqbal

Mustehssun Iqbal

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usmiunique said:
U have 2 dices that u throw right!
Both dice dice can have any value from 1 to 6.. The score is the sum of the numbers on the two dices!
In that diagram, we take all possible values like if we assume the score in the first dice is 1, then the corresponding score on The second dice can be any number from 1 to 6.. Just like that for 2,3,4,5 and 6 is done. Both numbed are added together to give the score and hence ALL possible scores are noted in that table!
Click to expand...
got it... that was what i attempted before, might have been a mistake in calculations then. Thanks a lot :)
 
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shan5674

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usmiunique said:
ASA,​
i wanted to know when to take the mean of the data when calculating the quartiles.​
for eg. in M/J/2010 paper 61 stats,​
in question 2, we get the following steam-and-leaf diagram.​
0|2 5 6 8 8 (5)​
1|2 4 6 7 7 9 (6)​
2|1 2 3 3 3 5 6 7 (8)​
3|1 5 (2)​
now in calculating the median, we will divide the total number of data by 2 which in this case is​
21/2=10.5 so, which value will we take? 10 th value or 11thvalue or the mean of the 10th and 11th value.​
also in calculating the lower quartile, we get 21/4=5.25 here also, do we take the 5th value or the 6th value or the mean of the 5t and 6th value?​
again in calculating the upper quartile, we get 21*0.75=15.75 here again do we take the 15th value or the 16th value or the mean of the 15th and 16th value?​
sometimes in the mark scheme i have seen them taking the mean and sometimes the value immediately next to it.. im confused as to what should i do?​
WILL appreciate any help!​
Click to expand...

When ever you get a number that isnt a whole number you round it off to the next number. Thats what i was told and that is what i follow and so far havent come across any problems.

For your first example of 10.5 you use the 11th vaule and 5.25 you use the 6th vaule and for the next one the 16th value :)
 
mominzahid

mominzahid

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mukki said:
since the time for the standard journey is between two times use P(x1<X<x2) which becomes P(-z<Z<z) for such types of qs. so ul get 2fi(z)-1=.34
Click to expand...
I dont get it.. :(
:cry:
can u please explain it in more simpler terms? :(
i dont get wht u assumed x1 and x2 to be and what 2fi(z)-1=0.34 means?
 
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shan5674

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