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Mathematics: Post your doubts here!
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thankss a lot 
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it is given that f(x) = e^x sin(x/2)
show that F(x)>0 for all real values of x between 0 and 2 pi
Calculate the area enclosed by the curve f(x), the axis from 0 to x= 2 pi
show that F(x)>0 for all real values of x between 0 and 2 pi
Calculate the area enclosed by the curve f(x), the axis from 0 to x= 2 pi
I have Question Please solve it with Explanation..
A mother has found that 20% of the children who accepts the invitation to her children's birthday parties do not come.
For a Particular party she invites 12 children but only has 10 party hats.
1) What is the Probability that there is not a hat for every child who comes to the party ? [ans :0.275]
The Mother Knows that there is a probability of 0.1 that a children who comes to a party will refuse to wear a hat.
2) If this is taken into account,What is the Probability that there will not be a hat for every child who wants one ? [ans:0.110]
A mother has found that 20% of the children who accepts the invitation to her children's birthday parties do not come.
For a Particular party she invites 12 children but only has 10 party hats.
1) What is the Probability that there is not a hat for every child who comes to the party ? [ans :0.275]
The Mother Knows that there is a probability of 0.1 that a children who comes to a party will refuse to wear a hat.
2) If this is taken into account,What is the Probability that there will not be a hat for every child who wants one ? [ans:0.110]
PrecoiusPearl said:
Minimun value of SInx=0......and any value of x in e^x doesnot give negative value...thus f(x) is positive...so, now u can put x=0 when SinX/2 will b the list...!! and....Sin90=1 which the highest...so..to get Sin90..u have to put x=pi...so that u could get Sinpi/2 which is equal to 1...put e^pi..and show it..coz...
XPFMember
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^J07 = june 2007 i.e. s 07
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Hi, anyone please help me in these questions ! 3 ii, 6 i, 8 i and 11 from M /J 08 P1.. Will highly appreciate the time u serve on solving. Thanks!
http://www.xtremepapers.com/CIE/Interna ... 8_qp_1.pdf
http://www.xtremepapers.com/CIE/Interna ... 8_qp_1.pdf
Can someone tell me how to do question 3 B and 5 ii
http://www.xtremepapers.com/CIE/Interna ... 7_qp_6.pdf
http://www.xtremepapers.com/CIE/Interna ... 7_qp_6.pdf
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^haha no problem for the view goin out, Thanks a lot
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Quadratics
I know its easy but
x^4 - 5x^2 + 4 = 0 !
How to solve this one ??
I know its easy but
x^4 - 5x^2 + 4 = 0 !
How to solve this one ??
^
x^4 - 5x^2 + 4 = 0
Factorising
(x^2-1)(x^2-4)=0
x^2 = 1 or x^2 = 4
so x= + or - 1 OR x=+ or - 2
Note: Just think of the x^4 as x^2. You may substitute y=x^2 if you wish.
Then you'll get y^2-5y+4=0.
Just pick the method you're most at ease with such questions.
x^4 - 5x^2 + 4 = 0
Factorising
(x^2-1)(x^2-4)=0
x^2 = 1 or x^2 = 4
so x= + or - 1 OR x=+ or - 2
Note: Just think of the x^4 as x^2. You may substitute y=x^2 if you wish.
Then you'll get y^2-5y+4=0.
Just pick the method you're most at ease with such questions.
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@Anahita16 i just solved it myself two minutes before ! Anyway, thanks !
Anyway, thanks ! 
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thank GOD..........ALHAMDULILAH i got some knowledge about permutations nd combinations.............but one things teasing me what to do when they ask that e.g. tell the arrangements when 5 girls are not together given there are 5 girls and 6 boys ? :unknown: :unknown:
thanks
thanks
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You first find out the number of permutations when 5 girls are together and then subtract it from the total number of permutations.Silent Hunter said:thank GOD..........ALHAMDULILAH i got some knowledge about permutations nd combinations.............but one things teasing me what to do when they ask that e.g. tell the arrangements when 5 girls are not together given there are 5 girls and 6 boys ? :unknown: :unknown:
thanks