Mathematics: Post your doubts here!

[mrpaudel]

http://www.xtremepapers.com/CIE/International%20A%20And%20AS%20Level/9709%20-%20Mathematics/9709_w10_ms_33.pdf but the answers are different??

method varies..answer wont b different...!! do as i say..u will score an A for sure...!!

 

[PrecoiusPearl]

thankss a lot

 

[mrpaudel]

thankss a lot

hit the thank button too..if it helped!!

 

[PrecoiusPearl]

it is given that f(x) = e^x sin(x/2)
show that F(x)>0 for all real values of x between 0 and 2 pi
Calculate the area enclosed by the curve f(x), the axis from 0 to x= 2 pi

 

[slayers]

I have Question Please solve it with Explanation..

A mother has found that 20% of the children who accepts the invitation to her children's birthday parties do not come.
For a Particular party she invites 12 children but only has 10 party hats.
1) What is the Probability that there is not a hat for every child who comes to the party ? [ans :0.275]
The Mother Knows that there is a probability of 0.1 that a children who comes to a party will refuse to wear a hat.
2) If this is taken into account,What is the Probability that there will not be a hat for every child who wants one ? [ans:0.110]

 

[sagystu]

which question?

omg i am soo stupid
thank u any way i have already known it thank if u could help in this one though i would be gratfull
j07 -41 NO.5II

THANKS ALOT

 

[mrpaudel]

it is given that f(x) = e^x sin(x/2)
show that F(x)>0 for all real values of x between 0 and 2 pi
Calculate the area enclosed by the curve f(x), the axis from 0 to x= 2 pi

Minimun value of SInx=0......and any value of x in e^x doesnot give negative value...thus f(x) is positive...so, now u can put x=0 when SinX/2 will b the list...!! and....Sin90=1 which the highest...so..to get Sin90..u have to put x=pi...so that u could get Sinpi/2 which is equal to 1...put e^pi..and show it..coz...

 

[mrpaudel]

I have Question Please solve it with Explanation..

A mother has found that 20% of the children who accepts the invitation to her children's birthday parties do not come.
For a Particular party she invites 12 children but only has 10 party hats.
1) What is the Probability that there is not a hat for every child who comes to the party ? [ans :0.275]
The Mother Knows that there is a probability of 0.1 that a children who comes to a party will refuse to wear a hat.
2) If this is taken into account,What is the Probability that there will not be a hat for every child who wants one ? [ans:0.110]

I didnot understand ur question...sorry!!

 

[mrpaudel]

which question?

omg i am soo stupid
thank u any way i have already known it thank if u could help in this one though i would be gratfull
j07 -41 NO.5II

THANKS ALOT

J07 means which one? i have only heard bout w07 and s07 till now..!!

 

[XPFMember]

^J07 = june 2007 i.e. s 07

 

[rz123]

Hi, anyone please help me in these questions ! 3 ii, 6 i, 8 i and 11 from M /J 08 P1.. Will highly appreciate the time u serve on solving. Thanks!

http://www.xtremepapers.com/CIE/Interna ... 8_qp_1.pdf

 

[panda222]

Can someone tell me how to do question 3 B and 5 ii

http://www.xtremepapers.com/CIE/Interna ... 7_qp_6.pdf

 

[anahita16]

Hi, anyone please help me in these questions ! 3 ii, 6 i, 8 i and 11 from M /J 08 P1.. Will highly appreciate the time u serve on solving. Thanks!

http://www.xtremepapers.com/CIE/Interna ... 8_qp_1.pdf

well i've no idea why half the page went out of view :sorry:

 

[rz123]

^haha no problem for the view goin out, Thanks a lot

 

[VelaneDeBeaute]

Quadratics
I know its easy but
x^4 - 5x^2 + 4 = 0 !
How to solve this one ??

 

[anahita16]

^
x^4 - 5x^2 + 4 = 0
Factorising
(x^2-1)(x^2-4)=0
x^2 = 1 or x^2 = 4
so x= + or - 1 OR x=+ or - 2

Note: Just think of the x^4 as x^2. You may substitute y=x^2 if you wish.
Then you'll get y^2-5y+4=0.

Just pick the method you're most at ease with such questions.

 

[VelaneDeBeaute]

@Anahita16 i just solved it myself two minutes before ! Anyway, thanks !

 

[Silent Hunter]

thank GOD..........ALHAMDULILAH i got some knowledge about permutations nd combinations.............but one things teasing me what to do when they ask that e.g. tell the arrangements when 5 girls are not together given there are 5 girls and 6 boys ? :unknown: :unknown:

thanks

 

[abcde]

thank GOD..........ALHAMDULILAH i got some knowledge about permutations nd combinations.............but one things teasing me what to do when they ask that e.g. tell the arrangements when 5 girls are not together given there are 5 girls and 6 boys ? :unknown: :unknown:

thanks

You first find out the number of permutations when 5 girls are together and then subtract it from the total number of permutations.

 

[nikhil000]

HEy in need an urgent help .. P6-May-june 2008 last question..Plz Plz help me out !