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We have to take the domain of the inner function which is fwhy are they taking the domain of gf(x) to be lesser than 1?
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We have to take the domain of the inner function which is fwhy are they taking the domain of gf(x) to be lesser than 1?
This doesn't become a composite function like that! isn't the range of f(x) the domain of g(x)??We have to take the domain of the inner function which is f
Actually yes the answer is 2/3 but you people are saying the wrong concept,This doesn't become a composite function like that! isn't the range of f(x) the domain of g(x)??
Is this the official ms?
Like all the questions I've solved is literally nothing like this!
range of f(x) is equal to the domain of f inverserange of f(x) is equal to range of its inverse
We NEED the domain to calculate the range of the function fx. How can we do this without it?Actually yes the answer is 2/3 but you people are saying the wrong concept,
since range of f(x) is >4, substiuting 4 in g(x), it gives us 2/3 therefore 0<gf(x)<2/3 but we don't take the domain of f(x)
You're rightrange of f(x) is x<1
range of gf(x) is x>4
I have no idea what method are you using but using my method is the same answer, I'm still taking the fact that x<1 when I say f(x)>4We NEED the domain to calculate the range of the function fx. How can we do this without it?
Yes please can we stay calm Im freaking out now //Actually everyone is right. We all are saying the same thing in different ways![]()
That's not specified in the syllabus but questions do comeFor m/j 2019 is rate of change of cone included in the AS P1 syllabus?
Which year of the examiner report is this? I think if we make our line prominent then it's not an issueIn examiner report it is mentioned that we cannot place minus sign on printed line. Does this apply to fractions, dy/dx and square roots as well?
2016 +Which year of the examiner report is this? I think if we make our line prominent then it's not an issue
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