IgoforA said:another one from same year.. please help.
u make sure u put dN and dt on the numerator..this is the 1st key...!! so..
dN/{N(1800-N)} =1/3600 * dt
now.....use partial fractions..suppose this way......1/{N(1800-N)}=A/N + B/(1800-N) and find A and B...i hope u can solve this one....otherwise look at the book....find A and B..put in that equation........now integrate each term this way..
AlnN+ (-B)ln(1800-N) =ln3600 +c ----------------(1)
now put the given values of N as 300 and t as 0 in that equation to find c....and after u find c, put its value in equation (1)
and find expression for N..if u didnot get it, i will write it..and post it here..!!