- Messages
- 1,660
- Reaction score
- 11,026
- Points
- 523
nope
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
thanks a loti)
If the two chosen values are the same, Y takes the value 0. If they are not the same, then Y = Larger X - Smaller X.
Hence, the possible values Y can take are 0, 2 and 4.
Now to draw the table, we need the probabilities.
P(Y = 0) = P(X = 2 and 2) + P(X = 4 and 4) + P(X = 6 and 6)
= (0.5)² + (0.4)² + (0.1)²
= 0.42
P(Y = 4) = P(X = 2 and 6) + P(X = 6 and 2)
= (0.5)(0.1) + (0.1)(0.5)
= 0.1
P(Y = 2) = 1 - P(Y = 0) - P(Y = 4)
= 0.48
ii)
E(Y) = 2(0.48) + 4(0.1) = 1.36
thxno sketch only
nooo stats is breaking me uphaha pretty much the same here.. How's maths for ya.. ? should be pretty easy after last year.. right?
can u pls solve it?http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_61.pdf
Question 2: Explain it as much as you can and solve it completley .. since I don't understand it at all :S
Dug PhyZac and anyone else who has statistics
EDIT: Ah Got It.. It was tricky .. but opening the bracks did the trick...
I assume you have used the following method.https://www.xtremepapers.com/community/members/dug.23386/
please help me with no 6ii? is there any shortcut method? thanks in advance
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_ms_62.pdf
can u pls solve it?
Thank you so much for the clear explanationokay, i'll try to explain.View attachment 22873
First you have to find the length of the blue line. you have to use ' cos' to find it, lets call this line AX
so,
AX= 5c0s0.6 = 4.12 cm
now you will have to find the small length PX. to find PX u need to know the length of AQ, the length of AQ is 5cm because 'BQD' is an arc of a circle with center 'A' so it means its 5cm (the length AQ is the radius of the circle with center A)
so since u know AQ = 5cm, to find PX :
PX = 5 - 4.12 = 0.873 cm
but they are asking us for the length of PQ, so the length is 2*PX
===> PQ = 2*0.837
= 1.75 cm
hope u understood
thanks a lottThe method i use is very simple.
Just remember two things.
Ex = mean * n
E(number) = number * n
where n is the total number of people or frequency.
n = 24
E(x-36)=-60
Ex-E36=-60
Ex=-60+E36
Ex=-60+(24*36)
Ex=804
E(x-36)^2 = 227.76
E(x^2-72x+1296) = 227.26 (We just opened the square via the (a-b)^2 = a^2 -2ab + b^2
Ex^2-72Ex+E1296 = 227.26
Ex^2=227.76+72(Ex) - E1296
Ex^2=227.76+72(804) - 24*1296
Ex^2=27011.76 or 27000 (3sf)
thanks againI assume you have used the following method.
3 : 111
4 : 112, 121, 211
5 : 113, 131, 311, 122, 212, 221
6 : 123, 132, 312, 213, 231, 321, 114, 141, 411, 222
You can make it shorter by using permutation.
3 : 3!/3! = 1
4 : 3!/2! = 3
5 : 3!/2! + 3!/2! = 6
6 : 3!/2! + 3!/2! + 3!/2! + 3!/3! = 10
This can be done by intuition alone. I just showed you the working to make you understand. Hope you got it!!
thanks!!! dats simple, i wrote dat by mistake.. i'm sorry. i cudnt solve qs 3In Case = P(C) = 0.7
Not In Case = P(C`) = 0.3
Finds It = P(F)
CF = 0.7*1
C`F = 0.3*0.2
This question is pretty simple .. Just draw a tree diagram to solve it easily.
The Pen was in his case given that he finds it means.
P(In Case Given He Finds It)= (It was in Case and he finds it) over [ (It was in case and he finds it) + (It was not in case but he still finds it) ]
P(in C given F)= (CF)/(C`F+CF)
= 0.7*1/(0.7*1)+(0.3*0.2)
=0.7/0.7+0.06
=0.7/0.76
oh its ok i found the ans..thanxwhat didnt u get in no.3?
i just did the whole thing.check it again and sry i forgot to put 2x in the superscript value
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now