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Mathematics: Post your doubts here!

Ashique

Ashique

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AlishaK

AlishaK

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AlishaK said:
Using s=ut+0.5at^2, Hp=12t+0.5(-10)t^2 => Hp=12t-5t^2
Hq=7t+0.5(-10)t^2 => Hq=7t-5t^2
Given that 3Hp=8Hq, therefore, 3*(12t-5t^2)=8*(7t-5t^2), I hope you can take it further from here. t=0 or t=0.8s
Now using v=u+gt,
V of P at t=0.8s: v=12+(-10)(0.8), V of Q at t=0.8s: v=7+9-10)(0.8)....Hopefully it hits your brain.
Click to expand...
Ahmedraza73 Here u go!!
 
Ashik

Ashik

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p3 O/N 2007
10.) The straight line l has equation r = i + 6j − 3k + s(i − 2j + 2k). The plane p has equation
(r − 3i).(2i − 3j + 6k) = 0. The line l intersects the plane p at the point A.
(i) Find the position vector of A.
(ii) Find the acute angle between l and p.
(iii) Find a vector equation for the line which lies in p, passes through A and is perpendicular to l.

I could solve (i) and (ii) but got stuck with (iii), somebody help me out, exams knocking the door, need the answer as soon as possible :cry::(

In Addition:
If Possible please send some notes on
p3 : Complex numbers in polar form ( How to draw Argand Diagram from A to Z ) :( :cry::(:cry:
S1 : Permutation and Combination ( A to Z ) :( :cry:​
 
F

freezingfires

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PhyZac Can you please help me with November 2001 paper 6 Question 7.I'd be grateful if you gave a detailed explanation.Thanks!!
Here is the question:
A bag contains 7 orange balls and 3 blue balls.4 balls are selected at random from the bag,without replacement.Let X denote the number of blue balls selected.
i.Show that P(X=0)=1/6 and P(X=1)=1/2
ii.Construct a table to show the probability distribution of X.
 
Esme

Esme

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How was mechanics, you guys ? Mine was good Alhamdulillah... :)
No discussion of the questions allowed though :p
 
AlishaK

AlishaK

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Esme said:
How was mechanics, you guys ? Mine was good Alhamdulillah... :)
No discussion of the questions allowed though :p
Click to expand...
Till Q 5 it was perfect Alhamdulillah! messed up a bit in Q6 ii) thou. :/
But hopefully it was good. :D
Cheers! now math p3 and chem p4 !! Life never gives us a break! :p
 
applepie1996

applepie1996

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Wajih ul hassan said:
need help with paper 3 may/ june 2009 question no. 6
Click to expand...
ummm okay :)
here's part 1 )
dy/d(t)=3asin^2t(cost)
d(x)/d(t)=-3a sint cos^2t
d(y)/d(x)=3a sin^2t cost/-3a sint cos^2t
dy/d(x)=-tant

now for part 2 (the tricky bit :p )
.gradient=-tant , x=acos^3t, y=asin^3t
y-asin^3t= -tant(x-acos^3T)
y-asin^3t=-(sint/cost)x+(sint/cost)acos^3t
ycost-asin^3tcost=-xsint+asintcos^3t
xsint +ycost=asintcost(cos^2t+sin^2t)
xsint+ycost= asintcost

and part 3 :)
for y-intercept put y=0,
xsint+o= asintcost
x=acost
for y-intercept put x=0
0+ycost=asintcost
y=asint
coordinates of x are (acost,0)
coordinate of y are (0, asint)
lenght=((acost)^2+(asint)^2)^1/2
=(a^2cost^2+a^2sint^2)^1/2
=(a^2(cos^2t+sin^2t))^1/2
=(a^2)^1/2
=a
you get it ?
 
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