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Mathematics: Post your doubts here!

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Snowysangel and kitkat <3 :P

yeaahhh me too!! one of my forces is 5.2N and the other is 6.4 N

I considered the weight of the ring too ....
and i dont think the ring is fixed....

even if so.... how come one of my forcess is accurate while the other isn't?! >_< even thought i used one (THE APPARENTLY WRONG ONE) to calculate the other one (WHICH CAME OUT TO BE CORRECT)

cud it be that the ms is wrong?? has anyone seen if the er has anything to say about this?
from what i see the weight is either not included cause
a) ms is wrong
b) the examiner also wants us to break the weight into components and if we do none of them are parralel or horizontal
 
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View attachment 42218

i didnt get wat u just said about trial and error... where are we using trial and error here??? :eek:

and Why in the HELLO r we using u=F/N
what is THAT?! >__< i swear i dont know wat i;m gonna do in the paper tomorrow!! :O
I was giving an example..you can get a right answer in ALGEBRA through trial and error even though that's not usually the systematic method.
N is the contact force/normal reaction. Friction= mule x contact force...they just manipulated the equation
 
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Could someone explain why the vertical component of the tention in A pushes upward when the ring is on the point of sliding up in part II
 
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yesss PLISS!! :')

and is there NO ONE who did it like i did?? by finding angles and all??
I did. Got the wrong answer. The question is strange. I mean there is something that is supporting the weight of the ring. And it can't be friction alone, because in the very next question, we use the vertical component of the tension to balance it
Suchal Riaz Saad Mughal Any idea?
 
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