i am just warning you donot be over confident. no offence meant.i have also seen that!!
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Maths, Addmaths and Statistics: Post your doubts here!
- Thread starter OakMoon!
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Didn't get it
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i am just warning you donot be over confident. no offence meant.
I am over confident as hell, and i know it will cost me
and in math i find the questions require multiple calculation to find a simple thing and that lowers my grade due to silly mistake as chances of mistakes increase.
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lol i am not being that..i am just warning you donot be over confident. no offence meant.
i was just saying it DOES make it easier and thats a fact!
yup i admitt that. but i felt i should warn you guyz to not do it you know as they say "lol i am not being that..
i was just saying it DOES make it easier and thats a fact!
history repeats itself"
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yup i admitt that. but i felt i should warn you guyz to not do it you know as they say "
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Isn't this for anti-clockwise :OThanks alot
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exactly.. and i tend to miss out workings .. as i do them in my mind mostly .. lol and in calculator .. I forget to write them on the paper!
nope i have the habbit of writting each and every thing done on paper because in my view it it always saved me a mark or two and this helps in rechecjing as well
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Q. Given that f(x)=2x^2-5x-7.
And then.......sketch the graph of y=|f(x)| for -2<=x<=4.5. How to remove this modulus sign???
Plz plz plz anyone help!
asd: I think ur the only one capable of doing this
And then.......sketch the graph of y=|f(x)| for -2<=x<=4.5. How to remove this modulus sign???
Plz plz plz anyone help!
asd: I think ur the only one capable of doing this
um we have to draw the graph of the modulated function or the unmodulatedQ. Given that f(x)=2x^2-5x-7.
And then.......sketch the graph of y=|f(x)| for -2<=x<=4.5. How to remove this modulus sign???
Plz plz plz anyone help!
asd: I think ur the only one capable of doing this
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What do you mean?
i mean we only have to draw the graph of the modulated function whats hard in that
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Ok.....plz edit the equation and plz give me the final one based on which I can draw it.i mean we only have to draw the graph of the modulated function whats hard in that
you see y= l2x^2-5x-7l now draw it for the domain. simpleQ. Given that f(x)=2x^2-5x-7.
And then.......sketch the graph of y=|f(x)| for -2<=x<=4.5. How to remove this modulus sign???
Plz plz plz anyone help!
asd: I think ur the only one capable of doing this
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No, that's clock wise
:O :/
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Simply draw the graph of the original equation. Now you will see the curve has a minimum point, because the coefficient of x^2 is positive. This minimum point (turning point) if exists below x-axis, ie. in -ve y-value, reflect that part above the x-axis, taking y=o as the reference line for reflection.Q. Given that f(x)=2x^2-5x-7.
And then.......sketch the graph of y=|f(x)| for -2<=x<=4.5. How to remove this modulus sign???
Plz plz plz anyone help!
asd: I think ur the only one capable of doing this
This is what modulus does. It always changes the negative y-values to +ve.