Maths, Addmaths and Statistics: Post your doubts here!

[haha101]

remember for if stated that points are collinear or parrallel it would always be k times of its collinear point !!

Kra k dikha bhai !

 

[khizer shahab]

Kra k dikha bhai !

FD= 3p+k(-4p+2q)

and FE= q-p

so

FD=K x FE

3p+k(-4p+2q) = qk-pk


solve the equation now !!

 

[haha101]

FD= 3p+k(-4p+2q)

and FE= q-p

so

FD=K x FE

3p+k(-4p+2q) = qk-pk


solve the equation now !!

Same kiya hai ! YOu try it out man !

 

[ashiqbal]

http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w06_qp_1.pdf
thankuuu soooo much!!!! but can u explain question no 8 part c of this ppr?..

just like square where we had to get all powers divisible by two, for cube we have to get all powers divisible by 3. so multiply it by 3*5*5 so it becoms 2^3 * 3^3 * 5^3(all powers divisible by three!)

 

[Durrani]

Each interior angle of a regular polygon is p times each exterior angle.
Find an expression, in terms of p, for
(a) an exterior angle,
(b) the number of sides of the polygon

answer plz

 

[ashiqbal]

FD= 3p+k(-4p+2q)

and FE= q-p

so

FD=K x FE

3p+k(-4p+2q) = qk-pk


solve the equation now !!

Same kiya hai ! YOu try it out man !

you both have got the logic correct but are doing it wrong!
for the first three co linear points B C and D, they have given the variable "k" . you cant assign the same variable to a different set of colinear points, ie F E and D. so you have to intriduce a new variable, eg "c"

FD = c FE
(3-4k)p + 2kq = -cp + cq
from comparing variables of q:
c= 2k
now compare variables of p:
3-4k = -(2k)
3=4k-2k
k=3/2!

 

[Durrani]

plz answr my qs

 

[bogus]

Each interior angle of a regular polygon is p times each exterior angle.
Find an expression, in terms of p, for
(a) an exterior angle,
(b) the number of sides of the polygon

answer plz

x+px= 180 so rearranging it brings x= 180/p+1
360/ (180/p+1) solve it and answer is 2p+2

 

[Durrani]

x+px= 180 so rearranging it brings x= 180/p+1
360/ (180/p+1) solve it and answer is 2p+2

i was really close to it, thanks

 

[syed1995]

you both have got the logic correct but are doing it wrong!
for the first three co linear points B C and D, they have given the variable "k" . you cant assign the same variable to a different set of colinear points, ie F E and D. so you have to intriduce a new variable, eg "c"

FD = c FE
(3-4k)p + 2kq = -cp + cq
from comparing variables of q:
c= 2k
now compare variables of p:
3-4k = -(2k)
3=4k-2k
k=3/2!

hamesha ki tarah .. chah gaye sir jee I was thinking of putting another variable in .. but thought with two unknowns it won't get solved ..

 

[bogus]

Good luck to all math victims.... I'm sure u could all use it
Advice : Never study maths on the last day

 

[syed1995]

x+px= 180 so rearranging it brings x= 180/p+1
360/ (180/p+1) solve it and answer is 2p+2

that question was one of the worst that i have faced .. me and my friend literally filled two pages with that question!

we were using the the n-2*180/n to solve it!

 

[syed1995]

Good luck to all math victims.... I'm sure u could all use it
Advice : Never study maths on the last day

Last day is Thursday, P2 is what I am honestly worried about.

 

[ashiqbal]

hamesha ki tarah .. chah gaye sir jee I was thinking of putting another variable in .. but thought with two unknowns it won't get solved ..

for these types of questions, they dont usually use one variable, two variables are always used.(remember mew and lamda?) anyway, if u have to solve for colinear, you usually have 2 variables. if not, you should add one yourself.

 

[syed1995]

for these types of questions, they dont usually use one variable, two variables are always used.(remember mew and lamda?) anyway, if u have to solve for colinear, you usually have 2 variables. if not, you should add one yourself.

why are you reminding me of mew and lambda ( .. and yeah 2 variables it is .. btw how would be we which side to add that new variable on ? or we can add it to either side ?

 

[ashiqbal]

that question was one of the worst that i have faced .. me and my friend literally filled two pages with that question!

we were using the the n-2*180/n to solve it!

i used the same formula, completed part (a) in three lines, then forgot that we had to find n in terms of p, and then filled the whole page trying to find actual value of n. actually, i first found out n in terms of p, then replaced (2p+2) in 360/n!

 

[ashiqbal]

why are you reminding me of mew and lambda ( .. and yeah 2 variables it is .. btw how would be we which side to add that new variable on ? or we can add it to either side ?

either side. i would recommend other side from where the variable is so that confusions are not created!

 

[bogus]

hamesha ki tarah .. chah gaye sir jee I was thinking of putting another variable in .. but thought with two unknowns it won't get solved ..

dude u could use ratio its much shorter ... make a column matrix for both expressions x on top y on bottom and cross multiply... no need for another variable like (3x+4xk
6y) check this way out!

 

[syed1995]

i used the same formula, completed part (a) in three lines, then forgot that we had to find n in terms of p, and then filled the whole page trying to find actual value of n. actually, i first found out n in terms of p, then replaced (2p+2) in 360/n!

lol ... mazay ka scene yeh tha .. kay jab hum teacher kay paas lay gaye .. tu wo bhi usi method say start hogaye cuz unhein hamara wohi method dikha tha .. n-2 wala ... haha 2 marks kay question mein 3 pages ki working and still no answer!

 

[syed1995]

dude u could use ratio its much shorter ... make a column matrix for both expressions x on top y on bottom and cross multiply... no need for another variable like (3x+4xk
6y) check this way out!

could you give an example ?