Maths, Addmaths and Statistics: Post your doubts here!

[Spidey21]

I dont think that this will be allowed share the model..
well if it can diff or integrate then it wont be allowed...:|

 

[asd]

I dont think that this will be allowed share the model..
well if it can diff or integrate then it wont be allowed...:|

integrate as in only with limits to give a final numerical value. It does not give an answer in expressions like 3x^3 +x^2 ... blah blah.
besides, this site => http://www.edexcel.com/subjects/Mathematics/Pages/ViewEditorial.aspx?editorial=152 says that
"those which can perform numerical differentiation and integration" may be used...

 

[Spidey21]

integrate as in only with limits to give a final numerical value. It does not give an answer in expressions like 3x^3 +x^2 ... blah blah.
besides, this site => http://www.edexcel.com/subjects/Mathematics/Pages/ViewEditorial.aspx?editorial=152 says that
"those which can perform numerical differentiation and integration" may be used...

are you giving Edexcel??

 

[asd]

are you giving Edexcel??

No, but it says it applies to GCE and GCSE too..

 

[Spidey21]

um...i wouldnt take that risk if i were you but your choice..

 

[Aqsa Mohd]

the point (2,5) , (3,3) , (k,1) all lie in a straight line.
(i) find the vale of k ?
(ii)find the eqation of the line. ?
some one plzz anss this as early as possible.

 

[asd]

(i) find the gradient of the first 2 points, and then equate it to the gradient of the last 2 points.
(ii) use "y-y1=m(x-x1) to find the equation where, m is the gradient, x1 is the x-coordinate, and y1 is the y-coordinate.

 

[asd]

Umm, maybe i can just take 2 calculators. this should work!

 

[asd]

the point (2,5) , (3,3) , (k,1) all lie in a straight line.
(i) find the vale of k ?
(ii)find the eqation of the line. ?
some one plzz anss this as early as possible.

And, the answers are, k=2, so the third point should be (2,1) and the equation of the line is y=2x+1

 

[Spidey21]

Umm, maybe i can just take 2 calculators. this should work!

yeah i guess it should..

 

[Spidey21]

the point (2,5) , (3,3) , (k,1) all lie in a straight line.
(i) find the vale of k ?
(ii)find the eqation of the line. ?
some one plzz anss this as early as possible.

(i) find the gradient of the first 2 points, and then equate it to the gradient of the last 2 points.
(ii) use "y-y1=m(x-x1) to find the equation where, m is the gradient, x1 is the x-coordinate, and y1 is the y-coordinate.

and yes this is the correct method...

 

[GetSomeLife]

http://www.xtremepapers.com/papers/...Calculator Version) (4024)/4024_w10_qp_11.pdf

Q24 (d) (ii) Please

 

[screamingskull]

http://www.xtremepapers.com/papers/...Calculator Version) (4024)/4024_w10_qp_11.pdf

Q24 (d) (ii) Please

I think you meant to say b(ii)
Anyways, since the rotation is anticlockwise about the origin then the matrix representing this rotation will be:
[0 -1]
[1 0]

make the x-axis and the y axis in rough and mark two points (1,0) and (0,1) on it then rotate them 90 degrees a.c.w so you will find that (1,0) ------> (0,1) and (0,1)---->(-1,0) and this is the Transformation Matrix.

 

[Mayedah]

http://www.xtremepapers.com/papers/...Calculator Version) (4024)/4024_w10_qp_11.pdf

Q24 (d) (ii) Please

Thre is no such part as d (!!)

 

[Spidey21]

Thre is no such part as d (!!)

please....thats d(ii)...not d(!!)

 

[Spidey21]

http://www.xtremepapers.com/papers/...Calculator Version) (4024)/4024_w10_qp_11.pdf

Q24 (d) (ii) Please

and there is no d (ii) -_-

 

[Mayedah]

please....thats d(ii)...not d(!!)

I cant make tht symbol the one in the bracket bcuz its not available ....best altenate yehi tha

 

[Spidey21]

http://www.xtremepapers.com/papers/...Calculator Version) (4024)/4024_w10_qp_11.pdf

Q24 (d) (ii) Please

the matrix will be

[-1 0]
[0 -2]

my guess...

 

[Mayedah]

the matrix will be

[-1 0]
[0 -2]

my guess...

The answer is
[0 -1]
[1 0]

 

[Spidey21]

The answer is
[0 -1]
[1 0]

but how?? :/