Maths, Addmaths and Statistics: Post your doubts here!

[snowbrood]

Sorry.

I meant QM=3... Read my post again... Scale factor is 2... Meaning that any side of the original image is to be doubled in length...

how to prove that MN=6

 

[ashiqbal]

http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_s11_qp_22.pdf can anyone solve Q10b(iii)

450/2

 

[Enferno]

450:550
9:11

9:11...
tell me is that right...
?

Plz explain fully

 

[snowbrood]

450/2

i kw this but can u explain why

 

[ashiqbal]

i kw this but can u explain why

u know the rule that "any angle subtending the diameter from a point on the circumference is 90 degrees", right? so reverse the rule so that it will become "any arc being subtended by a point on the circumference with an angle of 90 degrees is the diameter". I think i got this correct.

 

[youarecrazy4]

how do you find the center of rotation/the point about which the object is rotated?

 

[khizer shahab]

how do you find the center of rotation/the point about which the object is rotated?

1st join the original point with rotated point( repeat it for next point too)
2nd draw perpendicular bisector of both joint line.
3rd extend the bisector and mark the point where two bisector intersect.(that point is the point of rotation)
4th to find angle of rotation join the original point with bisected point and joint the same lint with rotated point, now measure the angle from bisected point.!!!

 

[Mayedah]

http://www.xtremepapers.com/papers/...(Calculator Version) (4024)/4024_w09_qp_2.pdf
Question no 11
Part a 4
The value of t when both objects had travelled the same distance !

 

[Translucent231]

The line CD is the perpendicular bisector of the line joining the point A (–1, –5) and the
point B (5,3). Given that M is the midpoint of AB, that 2CM = MD, and that the x-coordinate of C is – 2,
find the coordinates of D.

 

[Translucent231]

does the mark scheme of 4037_w11_ms_12 have wrong answer for question 8(i) ?? because w11_er has the correct answer but strangely mark scheme has wrong answer, wtf is this?

 

[snowbrood]

http://www.xtremepapers.com/papers/...Calculator Version) (4024)/4024_s11_qp_22.pdf can u solve q9c iii b

 

[Mayedah]

http://www.xtremepapers.com/papers/...Calculator Version) (4024)/4024_s11_qp_22.pdf can u solve q9c iii b

The part in which u hav to find gradient ?

 

[Mayedah]

The line CD is the perpendicular bisector of the line joining the point A (–1, –5) and the
point B (5,3). Given that M is the midpoint of AB, that 2CM = MD, and that the x-coordinate of C is – 2,
find the coordinates of D.

The coordinates of D will be (10,-7) but im not sure. ,
This question belongs from which past paper ?

 

[Spidey21]

Plz explain fully

well you have 450 : 550 right?
just simplify it and youll have your answer..

 

[Spidey21]

View attachment 7886 here it is again

more detail..
you know that total weight of leaves = 1000g (1kg)
Grade A leaves used will be 450g as given
Grade B leaves used will be 1000-450=550g

just rationalise them now...
450:550 (divide them by 10)
45:55 (divide them by 5)
9:11
TA DA!!

 

[snowbrood]

http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w09_qp_2.pdf
Question no 11
Part a 4
The value of t when both objects had travelled the same distance !

sorry this is the correct link
http://www.xtremepapers.com/papers/...Calculator Version) (4024)/4024_w11_qp_22.pdf Q9c iiib

 

[ashiqbal]

http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w09_qp_2.pdf
Question no 11
Part a 4
The value of t when both objects had travelled the same distance !

20x+50 =12x+60
t=x+5

 

[ashiqbal]

sorry this is the correct link
http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w11_qp_22.pdf Q9c iiib

AP=QB
PN=QM
therefore AN=BM=BM=6 cm

 

[snowbrood]

AP=QB
PN=QM
therefore AN=BM=BM=6 cm

how can u tell that PN=QM?? can u explain it

 

[ashiqbal]

how can u tell that PN=QM?? can u explain it

we would apply the rule of congruency here (AAS)
Angle MQB = Angle NPA
Angle QMB = Angle PNA
AP = QB
therefore QMB is congruent to PNA