Maths, Addmaths and Statistics: Post your doubts here!

[Spidey21]

I cant make tht symbol the one in the bracket bcuz its not available ....best altenate yehi tha

its the letter I...you dont have I ??

 

[Mayedah]

but how?? :/

its the letter I...you dont have I ??

I have it butused exclamation instead
And these are transformation by matrix .thre is a list of all of them . I have just learned them...no specific logic...thts wht i hear frm my teachers !

 

[Spidey21]

The answer is
[0 -1]
[1 0]

yes you are right...my bad...i told the new vertices but not the transformation matrix...

 

[Spidey21]

I have it butused exclamation instead
And these are transformation by matrix .thre is a list of all of them . I have just learned them...no specific logic...thts wht i hear frm my teachers !

well to be very honest the same is with me...

i have learned these exactly the same way...

 

[screamingskull]

And these are transformation by matrix .thre is a list of all of them . I have just learned them...no specific logic...thts wht i hear frm my teachers !

The logic is
since the rotation is anticlockwise about the origin then the matrix representing this rotation will be:
[0 -1]
[1 0]

make the x-axis and the y axis in rough and mark two points (1,0) and (0,1) on it then rotate them 90 degrees a.c.w so you will find that (1,0) ------> (0,1) and (0,1)---->(-1,0) and this is the Transformation Matrix.

I just posted this before but here it goes.

 

[Mayedah]

well to be very honest the same is with me...

i have learned these exactly the same way...

Yes u have no other way out ! I always forget thm :/

 

[Mayedah]

The logic is
since the rotation is anticlockwise about the origin then the matrix representing this rotation will be:
[0 -1]
[1 0]

make the x-axis and the y axis in rough and mark two points (1,0) and (0,1) on it then rotate them 90 degrees a.c.w so you will find that (1,0) ------> (0,1) and (0,1)---->(-1,0) and this is the Transformation Matrix.

I just posted this before but here it goes.

So does this method work for every transformation matrix ?

 

[Spidey21]

Yes u have no other way out ! I always forget thm :/

True..somewhat the same here...

So does this method work for every transformation matrix ?

[Making An Edit]

no you have to use different formula when the transformation is a translation...

 

[Mayedah]

The logic is
since the rotation is anticlockwise about the origin then the matrix representing this rotation will be:
[0 -1]
[1 0]

make the x-axis and the y axis in rough and mark two points (1,0) and (0,1) on it then rotate them 90 degrees a.c.w so you will find that (1,0) ------> (0,1) and (0,1)---->(-1,0) and this is the Transformation Matrix.

I just posted this before but here it goes.

Btw thnx for the explanation !

 

[screamingskull]

So does this method work for every transformation matrix ?

Yes ONLY IF IT HAS BEEN MENTIONED THAT THE TRANSFORMATION IS TAKING PLACE WITH THE ORIGIN AS ITS CENTRE.

 

[screamingskull]

Btw thnx for the explanation !

My Pleasure

 

[Spidey21]

Yes ONLY IF IT HAS BEEN MENTIONED THAT THE TRANSFORMATION IS TAKING PLACE WITH THE ORIGIN AS ITS CENTRE.

what if the transformation a translation???

 

[GetSomeLife]

The answer is
[0 -1]
[1 0]

but how?? :/

Yes ONLY IF IT HAS BEEN MENTIONED THAT THE TRANSFORMATION IS TAKING PLACE WITH THE ORIGIN AS ITS CENTRE.

Sorry guys But i seem to have asked the wrong question by mistake

24 d ii of THIS one is required:

http://www.xtremepapers.com/papers/...Calculator Version) (4024)/4024_w11_qp_11.pdf

 

[Spidey21]

Sorry guys But i seem to have asked the wrong question by mistake

24 d ii of THIS one is required:

http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w11_qp_11.pdf

MAN!! lol...jk..

 

[screamingskull]

what if the transformation a translation???

Then the situation is different. For translation usually a translation matrix is given and you ADD the matrix to your coordinates or matrix and their sum tells us the position of the image. The centre is not requires there.

 

[screamingskull]

Why youuu
Lol just kidding.

 

[Spidey21]

Then the situation is different. For translation usually a translation matrix is given and you ADD the matrix to your coordinates or matrix and their sum tells us the position of the image. The centre is not requires there.

yes thats what i am saying..

so for different transformations there are different formulas..

 

[Spidey21]

Sorry guys But i seem to have asked the wrong question by mistake

24 d ii of THIS one is required:

http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w11_qp_11.pdf

well the method is that you find AR in terms of p, q and l and then equate both the ARs to find out the value of K...

My Pleasure

share if there is another way...

 

[GetSomeLife]

well the method is that you find AR in terms of p, q and l and then equate both the ARs to find out the value of K...

Tried. Not getting the answer. =/

 

[Mayedah]

Sorry guys But i seem to have asked the wrong question by mistake

24 d ii of THIS one is required:

http://www.xtremepapers.com/papers/...Calculator Version) (4024)/4024_w11_qp_11.pdf

I have problem in the same part