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I meant to say that first we can assume value of 2. Then, solve them simultaneously. After that, work out the discriminant. If discriminant is positive, then it means that it intersects the curve in two distinct points.
wait i m solvingI meant to say that first we can assume value of 2. Then, solve them simultaneously. After that, work out the discriminant. If discriminant is positive, then it means that it intersects the curve in two distinct points.
I just started Add. Maths. So I'm not sure how to go for this question!
Ok thnx.....waiting!
Ok fine.....I'll be back at six. But just tell me whether my method is right or wrong?YAr I dont have time to type solution if u can wait till 6 it will be good q k light janay wali hai ..
I dont think it is right becoz in add maths we dont suppose anything except in trail and error method..
Ok.....plz plz plz do come up with a solution at 6 p.m. Thnx for your time!
No, arrange the first equation like this y=q-x
Oh, wait, when you multiply the equation with the -ve sign, the '>' will change to '<'No, arrange the first equation like this y=q-x
put this in the second equation given in place of y.
your final equation will be:
3x^2 +x(-2-4q) + 2q^2-3=o
Now, see the question says the line intersects the curve at 2 distinct points, So the b^2 - 4ac > 0
(-2-4q)^2 - 4 (3)(2q^2 -3) > 0
You will get q^2 - 2q -5 > 0
arrange it to q^2 > 2q+5
SHOWN.
Thnx a lot!Oh, wait, when you multiply the equation with the -ve sign, the '>' will change to '<'
Now, its perfect!
Haris Bin Zahid
How did the paper go today?
Oh....by the way I did a very long method. Instead of substituting, I formed an equation and squared (q-x), as in the other equation it was y^2.No, arrange the first equation like this y=q-x
put this in the second equation given in place of y.
your final equation will be:
3x^2 +x(-2-4q) + 2q^2-3=o
Now, see the question says the line intersects the curve at 2 distinct points, So the b^2 - 4ac > 0
(-2-4q)^2 - 4 (3)(2q^2 -3) > 0
You will get q^2 - 2q -5 > 0
arrange it to q^2 > 2q+5
SHOWN.
no maths till 1st june please
u got the solution.. ?? i also solved it should i tell u..?MustafaMotani
Well....I did it. Actually my teacher told me that method, but it seemed wrong. By the way I did it the right way!
Well...no thnx, I did it. It'll be a waste of time for you. Thnx for cooperation!
OhKWell...no thnx, I did it. It'll be a waste of time for you. Thnx for cooperation!
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