- Messages
- 23
- Reaction score
- 18
- Points
- 13
Inverse of a matrix:
|a b|
|c d|
is
[1/(ad-bc)] *
|d -b|
|-c a|
where ad-bc is the determinant and its inverse is a simply being multiplied to the matrix.
Order of a matrix is always rows x columns
|a b|
|c d|
is
[1/(ad-bc)] *
|d -b|
|-c a|
where ad-bc is the determinant and its inverse is a simply being multiplied to the matrix.
Order of a matrix is always rows x columns