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I wrote it wrong actually, wrote p as q.You hqve subtracted 6p and q. It was not 6p - p
He's right.
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I wrote it wrong actually, wrote p as q.You hqve subtracted 6p and q. It was not 6p - p
Yes very annoying lol. Value hi galat btai thi.But we have K with AE.
Can you please solve this further?
AE= 6p+kp-q
BC= 2p+q.
I know I'm very annoying.
Whatever it is nearest to, divide that by 2 to get the bounds.Can anyone explain explicitly about these stupid nearest cm , nearest kg and nearest 10s and all that? What the hell is that? I don't get a thing in that!
http://papers.xtremepapers.com/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w08_qp_1.pdf
Question 11 part b. anyone? It's related to the nearest kg. again.
So if it's nearest 10's of kg, degree whatever we'll divide 10 by two? And if it's 100 so we'll divide it by 2 as well.? When do we do 1/2?Whatever it is nearest to, divide that by 2 to get the bounds.
So the bound values of the box are 0.1/2 = ±.05 and for the container, they're 0.5/2 = ±0.25
You have to find the greatest possible mass, so use the + values of both bounds (each box is 1.55 kg and the container is 6.25 kg)
When it is correct to the nearest unit. For example, correct to the nearest kg.So if it's nearest 10's of kg, degree whatever we'll divide 10 by two? And if it's 100 so we'll divide it by 2 as well.? When do we do 1/2?
To find y:View attachment 43590
This. .-.
No...it is a bit tricky
i know that. but i dont understand where is their height?No...it is a bit tricky
here,s the deal
since OP is a common side side we just need to find the ratio of their heights right...
Since ba and op are paralle their HEIGHT component can be expressed as their ratio of lengths in general(if u wud like I will provide a detailed expl abt this)
so it simple becomes=(1/2 *OA*BA)/(1/2 *OA*OP)
so u will see it,s 1.5
For that area part, why don't we use the formula A1/A2= (l1/l2)^2 over here?No...it is a bit tricky
here,s the deal
since OP is a common side side we just need to find the ratio of their heights right...
Since ba and op are paralle their HEIGHT component can be expressed as their ratio of lengths in general(if u wud like I will provide a detailed expl abt this)
so it simple becomes=(1/2 *OA*BA)/(1/2 *OA*OP)
so u will see it,s 1.5
Yeah sorry.Yes very annoying lol. Value hi galat btai thi.
Rule is to eliminate all variables as K is a numeric value. -5q can be eliminated by +5q
main subah 2 bajay nae milta
Yeh kya bakwas method hai.12 c I would do it by a longer method but surer
View attachment 43605
Now see
OBA = 0.5 x (3a -2c) x (4a) x sin BAO
OPA = 0.5 x (2a- 4/3 c) x (4a) x sin AOP
when we divide them 0.5, 4a and the sine s get cut
simplify the remaining to get the answer
-_____- it is quite simpleYeh kya bakwas method hai.
do you not understand??OBA = 0.5 x (3a -2c) x (4a) x sin BAO
OPA = 0.5 x (2a- 4/3 c) x (4a) x sin AOP
when we divide them 0.5, 4a and the sine s get cut
simplify the remaining to get the answer
Yeh sin wgera kiun lagaya hai?-_____- it is quite simple
What part of
do you not understand??
we had a common angle and a common side and values for the other two as wellYeh sin wgera kiun lagaya hai?
After cutting we are left with 3a-2c/ 2a-3/4c.. How do we deduce the answer now?we had a common angle and a common side and values for the other two as well
to get a ratio you, can use the Area of triangle formula = 1/2 a x b x sin c for both and then divide them with each other
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