Thank you very much sir, for helping me again, god bless youmole=volume x concentration
volume=mole x 24
4(c)(i) 0.002 (mol); 0.1 x 0.02dm3 (e.g 20cm3/1000)
4(c)(ii) 0.001 (mol); 0.002/2 (becuz its 2H2O2:1O2 SO 2:1)
4(c)(iii) 0.024 (dm3); 0.001 x 24
4(c)(iv) no change/ no effect; (as catalysts don't affect equilibrium and thus the volume of the reactants-it just speeds up the reaction)
4(c)(v) 0.048 (dm3 ); 0.024 x 2 (as concentration is doubled )-e.g 0.1mol/dm3 x 2 = 0.2 mol/dm3
Hope it helps
Even at relatively low pressures, there is a 99.5% conversion of sulphur dioxide into sulphur trioxide. The very small improvement that you could achieve by increasing the pressure isn't worth the expense of producing those high pressures.hey guys
can someone help with this problem?
High pressure will increase the yield of SO3. why the reaction is carried at atmospheric pressure in the contact process?