Physics, Chemistry and Biology: Post your doubts here!

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Can anyone give me source where I can find sample and model answers to Planning Questions (last Question) to paper 6 (IGCSE) . I found a very useful video in this link below.
Can anyone suggest anything more.
 
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I need help with something in physics I hope I can still post my doubt can someone please explain sensitivity,range,speed of response and linearity what affects them in the LIG thermometer
 
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Hello! I am having problems in the Unit of Electromagnetism in Physics, I have doubts in b), bii), biii) and biv)
I have done A and C, can anyone help me
Can anyone mention the answers?Screenshot 2019-10-30 at 1.52.54 PM.png
 
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Hello! I am having problems in the Unit of Electromagnetism in Physics, I have doubts in b), bii), biii) and biv)
I have done A and C, can anyone help me
Can anyone mention the answers?View attachment 65039
if XY is moved horizontally in any direction, no magnetic field lines will be cut therefore no change would be observed on the pointer.
However, if XY is moved up and down repeatedly at right angles to the magnetic field, the magnetic field lines are cut and current is produced because the magnetic lines of force are applying a force on the free electrons in the conductor and causing them to move. So the answers will be:

(i) no change
(ii) no change
(iii) no change
(iv) pointer flickers between A and B
 
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Q: A cyclist travels along a horizontal track at constant speed. The work done by the cyclist is equal to :

can I pls get the answer
 
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Hello everyone, I need some help, can anyone please give me notes for Physics, Chemistry and Biology, thanks ;)
 
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View attachment 65163
View attachment 65164
View attachment 65165
How to do this, please help, I am not understanding this
mole=volume x concentration
volume=mole x 24


4(c)(i) 0.002 (mol); 0.1 x 0.02dm3 (e.g 20cm3/1000)
4(c)(ii) 0.001 (mol); 0.002/2 (becuz its 2H2O2:1O2 SO 2:1)
4(c)(iii) 0.024 (dm3); 0.001 x 24
4(c)(iv) no change/ no effect; (as catalysts don't affect equilibrium and thus the volume of the reactants-it just speeds up the reaction)
4(c)(v) 0.048 (dm3 ); 0.024 x 2 (as concentration is doubled )-e.g 0.1mol/dm3 x 2 = 0.2 mol/dm3

Hope it helps :)
Good luck!
 
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