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Physics, Chemistry and Biology: Post your doubts here!

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Q: A cyclist travels along a horizontal track at constant speed. The work done by the cyclist is equal to :

can I pls get the answer
 
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Hello everyone, I need some help, can anyone please give me notes for Physics, Chemistry and Biology, thanks ;)
 
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View attachment 65163
View attachment 65164
View attachment 65165
How to do this, please help, I am not understanding this

mole=volume x concentration
volume=mole x 24


4(c)(i) 0.002 (mol); 0.1 x 0.02dm3 (e.g 20cm3/1000)
4(c)(ii) 0.001 (mol); 0.002/2 (becuz its 2H2O2:1O2 SO 2:1)
4(c)(iii) 0.024 (dm3); 0.001 x 24
4(c)(iv) no change/ no effect; (as catalysts don't affect equilibrium and thus the volume of the reactants-it just speeds up the reaction)
4(c)(v) 0.048 (dm3 ); 0.024 x 2 (as concentration is doubled )-e.g 0.1mol/dm3 x 2 = 0.2 mol/dm3

Hope it helps :)
Good luck!
 
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Hello everyone, I need some help, can anyone please give me notes for Physics, Chemistry and Biology, thanks ;)
Here are some I use. Hope they r beneficial
 

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  • cie-igcse-physics-0625-theory-v4-znotes.pdf
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  • cie-igcse-chemistry-0620-theory-v2-znotes.pdf
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  • cie-igcse-biology-0610-theory-v2-znotes.pdf
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mole=volume x concentration
volume=mole x 24


4(c)(i) 0.002 (mol); 0.1 x 0.02dm3 (e.g 20cm3/1000)
4(c)(ii) 0.001 (mol); 0.002/2 (becuz its 2H2O2:1O2 SO 2:1)
4(c)(iii) 0.024 (dm3); 0.001 x 24
4(c)(iv) no change/ no effect; (as catalysts don't affect equilibrium and thus the volume of the reactants-it just speeds up the reaction)
4(c)(v) 0.048 (dm3 ); 0.024 x 2 (as concentration is doubled )-e.g 0.1mol/dm3 x 2 = 0.2 mol/dm3

Hope it helps :)
Good luck!
Thank you very much sir, for helping me again, god bless you
 
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