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Physics MCQs thread.

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@arlery... thankx
If you or anyone else could explain me the concept behind these questions, it would be really appreciated...
 
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Betelgeuse said:
@arlery... thankx
If you or anyone else could explain me the concept behind these questions, it would be really appreciated...

parallel combination main voltage divide nae hota.
so V2=V3.
V is divided into V1 and V2 OR V1 and V3
V = V1 + V3 OR V = V1 + V2
 
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make a second wave to the right of the original wave. u will see that A is moving down while C is moving upwards[/quote]

I tried that, but I still don't get it! :/[/quote]

can you pls show it on paint?[/quote]

yar mjhse achi wave nae ban rahi. ajib se ban rahi hai. lemme try again :(
 
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unique840 said:
make a second wave to the right of the original wave. u will see that A is moving down while C is moving upwards

I tried that, but I still don't get it! :/[/quote]

can you pls show it on paint?[/quote]

yar mjhse achi wave nae ban rahi. ajib se ban rahi hai. lemme try again :([/quote]

lol, i don't speak urdu/hindi! please do, and thanks alot!
 
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can you pls show it on paint?[/quote]

yar mjhse achi wave nae ban rahi. ajib se ban rahi hai. lemme try again :([/quote]

lol, i don't speak urdu/hindi! please do, and thanks alot![/quote]
 
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unique840 said:
can you pls show it on paint?

yar mjhse achi wave nae ban rahi. ajib se ban rahi hai. lemme try again :([/quote]

lol, i don't speak urdu/hindi! please do, and thanks alot![/quote][/quote]
but why did u draw it that way /
 
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but why did u draw it that way /[/quote]

cox jb wave aagay move karegi to esi hi banegi. wave k particles ki up ya down movement dekhne k liye new wave bana kar dekhte hain
 
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24 Two springs P and Q both obey Hooke’s law. They have spring constants 2k and k respectively.
The springs are stretched, separately, by a force that is gradually increased from zero up to a
certain maximum value, the same for each spring. The work done in stretching spring P is WP,
and the work done in stretching spring Q is WQ.
How is WP related to WQ?
A WP = 0.25 WQ B WP = 0.5 WQ C WP = 2WQ D WP = 4WQ
CAN some1 plz show the working??
WHY ITS B ?
 
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unique840 said:
cox jb wave aagay move karegi to esi hi banegi. wave k particles ki up ya down movement dekhne k liye new wave bana kar dekhte hain
sorry but can u plz repeat it in english ( i don't speak urdu)
 
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Hateexams93 said:
unique840 said:
cox jb wave aagay move karegi to esi hi banegi. wave k particles ki up ya down movement dekhne k liye new wave bana kar dekhte hain
sorry but can u plz repeat it in english ( i don't speak urdu)

ok. the wave will be like this when it moves forward. to find the up or down movement of the wave particles,we have to make a new wave like this.
sorry 4 replyin in urdu.
 
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Hateexams93 said:
24 Two springs P and Q both obey Hooke’s law. They have spring constants 2k and k respectively.
The springs are stretched, separately, by a force that is gradually increased from zero up to a
certain maximum value, the same for each spring. The work done in stretching spring P is WP,
and the work done in stretching spring Q is WQ.
How is WP related to WQ?
A WP = 0.25 WQ B WP = 0.5 WQ C WP = 2WQ D WP = 4WQ
CAN some1 plz show the working??
WHY ITS B ?

W.D = (1/2)*k*x
when force is constant, k is indiectly proportional to extension
for spring P, extention will be 1/2
for spring Q, extention will be 2
so w.d for P is (1/2)*2k*(1/2)
n w.d for Q is (1/2)*k*2
SO WP=0.5 of WQ
 
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unique840 said:
ok. the wave will be like this when it moves forward. to find the up or down movement of the wave particles,we have to make a new wave like this.
sorry 4 replyin in urdu.
if ts movement was to the left ,what will be the difference ?
 
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Hateexams93 said:
unique840 said:
ok. the wave will be like this when it moves forward. to find the up or down movement of the wave particles,we have to make a new wave like this.
sorry 4 replyin in urdu.
if ts movement was to the left ,what will be the difference ?

the new wave will be drawn to the left of the original wave
 
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unique840 said:
Hateexams93 said:
24 Two springs P and Q both obey Hooke’s law. They have spring constants 2k and k respectively.
The springs are stretched, separately, by a force that is gradually increased from zero up to a
certain maximum value, the same for each spring. The work done in stretching spring P is WP,
and the work done in stretching spring Q is WQ.
How is WP related to WQ?
A WP = 0.25 WQ B WP = 0.5 WQ C WP = 2WQ D WP = 4WQ
CAN some1 plz show the working??
WHY ITS B ?

W.D = (1/2)*k*x
when force is constant, k is indiectly proportional to extension
for spring P, extention will be 1/2
for spring Q, extention will be 2
so w.d for P is (1/2)*2k*(1/2)
n w.d for Q is (1/2)*k*2
SO WP=0.5 of WQ
how did u get extension 2 for Q ?
 
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