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Physics: Post your doubts here!

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Could anyone explain to me how to solve this question briefly??
Thanx in advance...
 

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Its not for elastic collision. That's for inelastic collision. In case of elastic collision the kinetic energy of the body is conserved so we have to use the another equation that I mentioned earlier. I guess you are clear now. :)
thanks!
 
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The Ans is Option D
That's because in free fall the rate of acceleration increases for the ball since the force of gravity is acting on it.
Besides,they've stated that it starts from rest.[From the origin that is]
Plot the same distance time graph as a velocity-time graph and you'll see what I mean.

You need to know the difference between displacement-time,distance-time,velocity-time and acceleration-time graphs in order to solve these types of questions.
 
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Resolve v :
1. You get v cos theta along X . So magnitude of X = v cos theta
But using mathematical knowledge :
Increasing theta form 0 to 90 degrees causes cos theta to decrease . Remember the graph for cos theta ? Do refer to it.
Hence along X , v cos theta decreases, so X decreases.

2. You get v sin theta along Y .So magnitude of Y = v sin theta .
But again applying mathematics:
Increasing theta from 0 to 90 degrees causes sin theta to increase . Refer graph of sin theta .
Hence Y increases.

Hope it helped!
Thanks mate.
 
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When a ball is dropped and allowed to fall under free gravity it will have three different stages- initially the resistance will greatly oppose the body, so the displacement/time graph would NOT be too steep but would (obviously) have a negative gradient. Then eventually, the ball will reach terminal velocity, where acceleration is 0 and the speed is constant, so you will get a straight line with a negative gradient. Then, finally will come a point where when the downward force will be much greater than the resistance (when it gets closer to the ground), hence the graph will be VERY steep.

From the description you can tell the answer is B. :)

Hey hey!But doesn't Ans B denote negative acceleration [aka retardation] ?!
I mean if you convert that h-t graph to a velocity time graph then it does make sense!
I think it should be Ans. D
And the gradient's only negative when a ball is thrown upwards [opposing the force of gravity as a result] -_-
 
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Hey Guys!
I'm in desperate need of someone's help! Can anyone post May/June 2002 past paper and the mark scheme
Please Please i need it for Tommorrow and didnt realise its not available on the website... anyone got it??
 
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may/june 2003 , paper1 , question : 5, 11, 17, 19, 22, nd q.40


please help!
 

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Hey Guys!
I'm in desperate need of someone's help! Can anyone post May/June 2002 past paper and the mark scheme
Please Please i need it for Tommorrow and didnt realise its not available on the website... anyone got it??
 

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hey guys can u help me out with jun 11?? i had lots of problem with
2, 20, 25, 35

and for the second variant:
Q2
Q3 why is the answer not D?
and Q9
 

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