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Did you check the mark scheme? Or do want the explanations of the answers?i need answers for AS mcq june 07 paper.question 7,8,10,11,12,13.
in the photoelectric effect Plx. explain me the difference between Photons and Photo electrons , I'm confused that when the electromagnetic radiation strikes the Cathode plate so is the radiation carrying photons or photo electrons and when -ve charges are emitted from this plate WHAT ARE THEY CALLED!!!!
june '05 q13) moments = force*perpendicular distancei need explanations for the answers of AS Qno. 13, 14 of paper 1 May/june 2005, Qno.15 of paper 1 of May/June 2006 and Qno. 7,10 and 13 of paper 1 of May/june 2007.
june '07 q10) force = momentum*timei need explanations for the answers of AS Qno. 13, 14 of paper 1 May/june 2005, Qno.15 of paper 1 of May/June 2006 and Qno. 7,10 and 13 of paper 1 of May/june 2007.
Q.8) u=0, s=30, a=10i need answers for AS mcq june 07 paper.question 7,8,10,11,12,13.
I was going through this question today when I realised that the explanation and the answer I gave to MCQ 9 above is utterly bogus. My apologies for the error! The correct answer is D. That's because the mass is moving up AND down on the end of a spring. Say the velocities are positive as it moves TO the lowest point (downward vertical motion). When it will move AWAY from the lowest point (upward vertical motion), the direction of motion is reversed so the velocities will attain negative values. Therefore, for the brief moment when the mass is AT the lowest point, the velocity would be zero.9. One way of dealing with this question is realising that at the lowest point, the velocity will have a maximum magnitude (min G.P.E and max K.E). Secondly, it will be negative since downward motion is ascribed a negative value. Hence, C is correct.
12. Momentum before collision = momentum after collision
m(-2v) + 3m(v) = 4m V
=> V = mv/4m = v/4.
Hence, A is correct.
phy P5 helppp??? ((((
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