Physics: Post your doubts here!

[kitkat <3 :P]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w10_qp_22.pdf

Guys PLEASE someone explain... Question 5 paper 21 !!
B part !
HURRYYY!! Please!!!
Thank u

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_qp_2.pdf

I'm sorry! Here u go! Paper 21 btw
And thank u

m sorry i tried alot but i cant solve it

 

[robinhoodmustafa]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_qp_2.pdf

I'm sorry! Here u go! Paper 21 btw
And thank u

I also wanted to ask this question. #same problem

 

[Asad Moosvi]

Guys, how do I check how many minima and maxima occur in question 5 part c? http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s13_qp_21.pdf

 

[robinhoodmustafa]

Guys, how do I check how many minima and maxima occur in question 5 part c? http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s13_qp_21.pdf

Aha! Welcome aboard to the same train #how to find no of minima and maxima

 

[robinhoodmustafa]

Guys how do we know to how many significant figures should we write the percentage error too??

Percentage so 3 Sig fig.

 

[Asad Moosvi]

Aha! Welcome aboard to the same train #how to find no of minima and maxima

Do you know how?

 

[usama321]

How

do you know I is 9?? I don't get what u just said

Read the part c) They say that the intensity of wave A at point P is I. Now intensity = A^2 and amplitude is the point of highest displacement on a wave. Seeing wave A, we can see that the amplitude is 3/-3. Thus, squaring it, we get 9, which the question states is I. We have to solve the rest of the parts in terms of this I

 

[kitkat <3 :P]

actually i think i got it look
we have the path difference that is 28
and the wavelength is 8.25
and its asking fo minima which is cuz of the destructive interference
so we will use the frmula pathdiff = (n+0.5)* lamda
= 2.89
n has to be in whole number cuz u know u cant have a half minima so n=2
m not sure thouh

I'm sorr


Sorry gave the link

 

[usama321]

Posted this a while ago DeViL gURl B)

m sorry i tried alot but i cant solve it

I also wanted to ask this question. #same problem

The wave from S1 has to travel 100cm. Using Pythagoras theorem, S2 will have to travel 128.1 cm.There is a path difference of 28.1 cm

Using v =f lambda, we know that
lambda= 330/1000 to 330/4000 Thus
8.25cm <= lambda <= 33 cm



Now, we know that a minima is formed when S2 is at its trough, while S1 at its crest. As both waves have the same frequencies, they will have travelled the same amount of distance in their respective first 100cm. However, in the next 28.1 cm, S2 must have travelled at least half, 1.5, 2.5 and so on cycles to cause destructive interference and thus a minima. We will check this with different possible wavelengths.

28.1 = 0.5 lamda
lamda = 56 cm. This is outside our range

28.1 = 1.5 lamda
lamda = 18.73. This is in our range

28.1 = 2.5 lamda
lamda = 11.24 cm This is in our range
28.1/3.5 = 8.02 Outside our range
answer = 2

 

[DeViL gURl B)]

I

m sorry i tried alot but i cant solve it

ita okhay .. Tough one!

 

[DeViL gURl B)]

actually i think i got it look
we have the path difference that is 28
and the wavelength is 8.25
and its asking fo minima which is cuz of the destructive interference
so we will use the frmula pathdiff = (n+0.5)* lamda
= 2.89
n has to be in whole number cuz u know u cant have a half minima so n=2
m not sure thouh

Can u please elaborate a bit more .. Please

 

[kitkat <3 :P]

Posted this a while ago DeViL gURl B)

matlab aweein bongi maari mainy thanks

 

[DeViL gURl B)]

Posted this a while ago DeViL gURl B)

Thank YOU SOOO MUCH!

 

[DeViL gURl B)]

matlab aweein bongi maari mainy thanks

Acha bongi thi btw.. Atleast u tried ..
Thank gal

 

[Asad Moosvi]

Need help. Quick! Q5 part c.
Someone please explain it ASAP! http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s13_qp_21.pdf

 

[kitkat <3 :P]

Acha bongi thi btw.. Atleast u tried ..
Thank gal

pori tarha se bongi nain thi bus ratty huye formula use kiye thy usama has elaborated it though

 

[DeViL gURl B)]

H

pori tarha se bongi nain thi bus ratty huye formula use kiye thy usama has elaborated it though

haha I know that's what I said achi bongi thi
Yeah thanks to him
Cuz this question was bugging me since a long time -_-

 

[kitkat <3 :P]

H

haha I know that's what I said achi bongi thi
Yeah thanks to him
Cuz this question was bugging me since a long time -_-

LOl n.p.
glad to know your prob has been solve

 

[usama321]

Need help. Quick! Q5 part c.
Someone please explain it ASAP! http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s13_qp_21.pdf

Calculate the path difference between the two waves. We get .15m Divide it by lambda and you get 6. This means that the wave from source S2 has travelled 6 whole waves more than S2 before reaching the point P. Furthermore, as 6 is a whole number, we also know that there is going to be constructive interference at P, leading to a maxima. Now, we also know that there would be maximas formed when wave S2 has travelled 5,4,3,2,1 extra waves. Thus we get 6 maximas in total. Include the maxima at O and you get 7 maximas with 6 minimas in between

 

[Asad Moosvi]

Calculate the path difference between the two waves. We get .15m Divide it by lambda and you get 6. This means that the wave from source S2 has travelled 6 whole waves more than S2 before reaching the point P. Furthermore, as 6 is a whole number, we also know that there is going to be constructive interference at P, leading to a maxima. Now, we also know that there would be maximas formed when wave S2 has travelled 5,4,3,2,1 extra waves. Thus we get 6 maximas in total. Include the maxima at O and you get 7 maximas with 6 minimas in between

Thank you. Could you please explain the equation we use to get 6? Why did you you divide the path difference by lambda?