Physics: Post your doubts here!

[Haya Ahmed]

new wave will be straight line.
Haya Ahmed please give him the pictures and animation which i gave you yesterday and explain it to him how i explained it to you. i have to solve many other doubts.

in 1/4 cycle antinode gets from highest point to zero. then in 1/4 it gets to lowest point then in 1/4 it gets to zero. then in 1/4 it gets back to max. so in one T it completes on cycle.


here is Suchal explanation
https://www.xtremepapers.com/commun...st-your-doubts-here.9860/page-440#post-782703
Physics: Post your doubts here!

 

[Suchal Riaz]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w10_qp_23.pdf
Q5 c)ii) ?????????????????? Plz Suchal Riaz

energy is directly proportional to square of extension. if E is half, then extension is 1/√2 of max extension = 2.6/√2 = 1.84

 

[Haya Ahmed]

please explain him that question in which i tagged you then i will answer your doubt.

Done .. now answer 2b ASAP ! :/

 

[Suchal Riaz]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s13_qp_22.pdf

guys how are we suppose to do q 5part b iii i dont get how we r suppose to draw the new wave

https://www.xtremepapers.com/commun...st-your-doubts-here.9860/page-451#post-784558

 

[Suchal Riaz]

Done .. now answer 2b ASAP ! :/

by conservation of energy the height of mass will be the same.
the height at A is 0.26
so height at second plank will be 0.26 m
height is 0.26, angle is 30 so the length = 0.26/sin30

 

[doremon]

Suchal Riaz do you think tomorrow's exam will be hard? and i am sorry for cussing

 

[Suchal Riaz]

Okay here's a questio!
A beam of alpha particles produces a current of 1.5 pA. Calculate the number of alpha particles per second passing a point in the beam. And please explain as well

current = charge/time
charge of an alpha particle = +4e
number of alph particle = n
total charge = n4e
current = 1.5 x 10 -12
so 1.5 x 10 -12 = 4ne/1 second
n=(1.5 x 10 -12)/4e = (1.5 x 10 -12)/4(1.6x10 -19) = 2.34 X 10 6

 

[Reddah Nadeem]

Heeyy guys can anyone lemme noe how to solve oct nov 5 question 3.c...Please..

 

[Suchal Riaz]

Suchal Riaz do you think tomorrow's exam will be hard? and i am sorry for cussing

idk the 2013 papers were easy as well as P1 of this year. but chemistry was different. and mechanics was difficult too. but i still hope it is easy.

 

[Suchal Riaz]

Heeyy guys can anyone lemme noe how to solve oct nov 5 question 3.c...Please..

post link. everyone posts link to get their question answered.

 

[doremon]

current = charge/time
charge of an alpha particle = +4e
number of alph particle = n
total charge = n4e
current = 1.5 x 10 -12
so 1.5 x 10 -12 = 4ne/1 second
n=(1.5 x 10 -12)/4e = (1.5 x 10 -12)/4(1.6x10 -19) = 2.34 X 10 6

I think you are wrong. charge of an alpha particle is +2 not +4!!!!!!!!!!!!!!!!!!!

 

[mehria]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w10_qp_22.pdf
Q4 (a) n (b) :/

 

[doremon]

mechanics was fudged up man

post link. everyone posts link to get their question answered.

 

[Haya Ahmed]

Physcis Revision Notes ! .. Read them and Please pray for me

 

[Suchal Riaz]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w10_qp_22.pdf
Q4 (a) n (b) :/

(a):
f=ke
energy = work done = average force * distance = 1/2 (F) * e
=1/2 fe
but f=ke so
=1/2 ke²

(b) each small block represent energy = 2N * 2 x 10^-5 m = 4 x 10^-5 J
count small boxex(put a dot in the one you have counted) and then multiply them by 4 x 10^-5

 

[Suchal Riaz]

now i am tired and i am going away bye :'(

 

[thats_me]

As u move along .. U know u see bright and dark fringes that is exactly what implies Here as well.. The dark fringes go for the minima and light go for the maxima .., in the same manner if u gi with the dots indicated .. U can say that If at O it is bright.. Then go along the dots and as u reach P is is maxima that is bright!
And u can say the readings go from maxima to minima ...and vice verse.
Hope it helps ya

Thanks! But how do we get the no. Of maxima & minima?

 

[unique111]

it was 5 ms which is =1/4T
it was initially at the 1/4th from my diagram so add 1/4 we get 2/4th stage.

Bro, could you explain the horizontal part again?

Then when do we draw this kind of graph (the red one being the new one?)

 

[unique111]

now i am tired and i am going away bye :'(

Oh, okay then. Thanks for all your help!

 

[ZaqZainab]

But the question didn't ask for drawing such diagrams ! I did this way and got the answer ! but I'm not sure did this answer 1 e (i) or not ! please someone correct me If I'm wrong !

Suchal Riaz

You guys confuse me
what i did was just made a line continue the wind line but with a little less angle