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Physics: Post your doubts here!

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1. For the dark fringe amplitude for first wave will be maximum and second will be minimum and so the phase difference is 180°.
2. For the bright fringe amplitude for both waves will be maximum.
At the bright fringe total amplitude will be 3.4 units and at dark fringe it will be 0.6 units. Intensity is proportional to square of velocity so ratio is 3.4^2/0.6^2=32
 
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1. For the dark fringe amplitude for first wave will be maximum and second will be minimum and so the phase difference is 180°.
2. For the bright fringe amplitude for both waves will be maximum.
At the bright fringe total amplitude will be 3.4 units and at dark fringe it will be 0.6 units. Intensity is proportional to square of velocity so ratio is 3.4^2/0.6^2=32
got it :) ty
 
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can anyone expalin me Q1 part c for physics november 2014 p2 variant 2 like how to show the resultant ? and the magnitude of resultant on B ?
 
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Can someone please explain the 85th question. The answer is actually: B.

THANKS IN ADVANCE!!!!!
 

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http://freeexampapers.com/A-Level/Physics/CIE/2010-Jun/9702_s10_qp_22.pdf
Question 2 b ii. shouldnt the distance be o.21? How come it is 90? SOMEONE????
And question 7 bii as well??

For 7 b) ii) 1. mass energy is conserved because the difference in mass is released is energy namely gamma radiation or kinetic energy.
Einsteins equation= e= mc^2
To put it simply, take the helium atom. To make a helium atom you would have to combine 2 protons and 2 neutrons.
If you were to calculate the mass of the 2 proton and 2 neutron, you would notice that the mass is slightly more than the actual mass of the helium atom.
This difference in mass is known as mass defect. Sub the mass defect into the e=mc^2 and you will be able to find the energy released when you form one helium atom.
So we normally say that the mass on the rhs is more than the mass on the lhs because energy is released.
2. 1.1MeV= 1/2mv^2
1.1*10^6*1.60*10^-19=1/2*9.11*10^-31*(v^2)
 
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Can someone please explain the 85th question. The answer is actually: B.

THANKS IN ADVANCE!!!!!
Resistance is the reciprocal of the gradient
For W-X, the graph is a straight line, this means that both pd and current are constant, hence resistance is constant
For X-Y to Y-Z, the gradient is increasing, hence, resistance is increasing.
 
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M/J 2007 Paper 4 Q5 (b)(ii)
State which combination, if any, of monochromatic light and metal surface could give rise to photo-electric emission. Give a quantitive explanation of your answer.

Can someone please help? Thanks!
 
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