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Does anyone have good notes regarding the problems and improvements for experiments?? This is for P3 practical.
Thanks in Advance !
Thanks in Advance !
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Because the lower three values can't be divided by 1.6, and 3.1 is close to 3.2 so there could have been an experimental errorhttp://maxpapers.com/wp-content/uploads/2012/11/9702_s12_qp_42.pdf
Can anyone help with this Q6b) part. Why isn't the ans 1.6x10^-19
Is .39 the value of e?We know that alpha( the intensity reflection coefficient ) is also = Ir/I
We need Ir
We got alpha in first part 0.33. From second part, I2=Ie^-ux
But since it's received back at the surface, it travelled twice the thickness, so it's 2x now.
So Ir= apha(I2)=0.33(0.39^2)(I)
This is why we square the fraction in part two.
Yeah, 0.39 from part two its e^-uxIs .39 the value of e?
Only the last two values cannot be divided by either 1.6 or 3.2.Because the lower three values can't be divided by 1.6, and 3.1 is close to 3.2 so there could have been an experimental error
E= -potential gradientView attachment 53850 Could someone explain to me how potential energy and field strength. Are related??
But 3.2 and 3.1 are closer than 3.2 is to 3.0 and 3.4 so the value by observation is 3.2..3 and 3.4 are the double of 1.5 and 1.7Only the last two values cannot be divided by either 1.6 or 3.2.
But in that question, field strength equals Potential gradient/ CHARGE....how did they get that?!E= -potential gradient
Electric field strength is the negative of gradient of Potential/distance graph
What is the question?But in that question, field strength equals Potential gradient/ CHARGE....how did they get that?!
The question says to derive the equation field strength= potential gradient x charge...I posted the msWhat is the question?
Can you please attach the paper?
okay i compiled some 2007-2011 application questions and answers. to grab em click here
The question says to derive the equation fiekd strength= potential gradient/ chargeWhat is the question?
Can you please attach the paper?
Isnt there anything regarding it in the examiners repory?Jazak Allah for this!
Please can you tell me the anwer for Q6)b) part. The answer to this is 3.2x10^-19, why cant it be 1.6x10^-19?
http://maxpapers.com/wp-content/uploads/2012/11/9702_s12_qp_42.pdf
They talk abput 1.6x10^-19 as the highest common factorIsnt there anything regarding it in the examiners repory?
Energy is potential into chargeThe question says to derive the equation fiekd strength= potential gradient/ charge
I posted the ms
from the data the difference between two smallest values is this. and all numbers are multiple of this.Jazak Allah for this!
Please can you tell me the anwer for Q6)b) part. The answer to this is 3.2x10^-19, why cant it be 1.6x10^-19?
http://maxpapers.com/wp-content/uploads/2012/11/9702_s12_qp_42.pdf
Aren't energy gradient and potential gradient the same thing?Energy is potential into charge
Potential is energy/charge
Gradient of potential=energy gradient/charge
ths is because we r talkng abt the torque... n the formula for the torque= force x (horizontal distance between the forces)
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