- Messages
- 9
- Reaction score
- 5
- Points
- 13
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
ONEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE
Thank you so much for your help. I just have a slight doubt, till now I was just aware that for RMS value we take Irms=I0/sqrt 2 so could you please briefly describe the area method used to answer it?
View attachment 59335
View attachment 59336
9702/s12/qp/23
Question 2 (c)
CAN SOMEONE PLEASE DRAW THE GRAPH AND UPLOAD A PICTURE OF IT?
Physicist I have to same doubt.Thank you so much for your help. I just have a slight doubt, till now I was just aware that for RMS value we take Irms=I0/sqrt 2 so could you please briefly describe the area method used to answer it?
I dont get how u did 3 * 0.5this is the case for any graph. i believe most teachers don't explain it this case. they only give the final result for a square graph. anyway, this is mostly maths.
Thank you so much for your help. I just have a slight doubt, till now I was just aware that for RMS value we take Irms=I0/sqrt 2 so could you please briefly describe the area method used to answer it?
When current is switched off , an emf is induced since theres a fall in the flux within the relay coil.View attachment 59339
Hey,
Could anyone, please explain me why do we use two diodes, when operating a relay.
The explanation given above doesn't seem consistent to me, since even if there is one diode D1, it won't allow the unwanted current to go to the op amp so how exactly is diode D2 helping anyway?
Thank you.
25J is change in internal energyThe b) part of the following is my doubt
In the ms for b part where did the 25J come from?
Current is reversed so flux linkage was +3 first and its now -3Hey
In this my doubt is the 5 c ii part
View attachment 59330View attachment 59331
View attachment 59332
So for averaging why are we multiplying the flux linkage by 2?
Please help, if possible.
part a
the I0/root2 is applicable for a sinusoidal waveform
For a square wave rms is same as peak
The factors for other waveforms are also given for you to have a look at
a) Magnetic field is always normal to Force and torque = force * perpendicular distance. So for maximum torque the plane of coil should be normal to MF so that its normal to force and gives maximum torque (Physicist correct me if m wrong as its my current topic going in school)http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s08_qp_4.pdf
Q6 a and b explanation please
Yeah, thanks No I just thought if you could have elaborated the method. Anyway, thank you so much. You have an amazing site btw.it is the way to obtain the Irms. of course, Irms is still a current.
From where did u get this?
the I0/root2 is applicable for a sinusoidal waveform
For a square wave rms is same as peak
The factors for other waveforms are also given for you to have a look at
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now