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http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w02_qp_2.pdf
Someone please help me with question 7 b(i), I don't understand the marking scheme.
Thanks
Ah .. they say that 1.1*10^5 J of energy was dissipated in the 45 ohm resistor .. how much energy will be dissipated in the 15 ohm resistor..
P= I^2 * R
P directly propotional to R
45 ohms produced 110 kJ 15 ohms will produce what?
45 -- 1.1 * 10^5
15 -- x
45x = 15 * 1.1 * 10^5
x = 3.67 * 10^4 Answer