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Q4- The diameter is 3.81. To find area 3.81/2 = radius wich is 1.9. and then pi *radius (square)Can someone PLEEASEEE help me with these questions?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s12_qp_12.pdf
4,18,22 25 26 28 35 38
i made a mistake in measuring the diameter..thankyouuu!Q4- The diameter is 3.81. To find area 3.81/2 = radius wich is 1.9. and then pi *radius (square)
10. F=4ma. a=F/4m. F(Y)=3m x F/4m = 3F/4.
22. F on each spring = W/3. F=kx. k=F/x=W/3x. x=F/k=W/W/3x=3x.
30. Average current=100+20=120/2=60. Q=It=60x8=480.
wow thats just like my grades in AS
I know its hard!! umm honestly u cant b sure about that. It all depends on the marks not the grades. Sometimes if u get an A in all papers u still end up with an overall A instead of the expected A* But dont worry ISA well do it My p4 was good what bout yours? I really wanted to discuss though! so do u wanna discuss or u forgot our answers? ;PYeah practical sucks . How was your P4? And what about my original question, can I get an A* if I get A in P4 and P5.
Q 22 - 1st of all calculate mass* 6.02*10^23. this gives u the mass of all atoms in the crystal. then find the volume by dividing the mass u calculated by density. density=mass/volume. Then divide volume by 6.02*10^23. and find its cube rootCan someone PLEEASEEE help me with these questions?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s12_qp_12.pdf
4,18,22 25 26 28 35 38
I know its hard!! umm honestly u cant b sure about that. It all depends on the marks not the grades. Sometimes if u get an A in all papers u still end up with an overall A instead of the expected A* But dont worry ISA well do it My p4 was good what bout yours? I really wanted to discuss though! so do u wanna discuss or u forgot our answers? ;P
Q5- x is 0.44. Add uncertainties. U get 0.03. (0.03/0.44)*100 = 7%http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w10_qp_12.pdf
I know I have a lot of doubts.. will be really grateful for help
Q5, 8, 14, 22, 25, 26, 33, and, 34
to profiles par discuss karayn?Mine went good as well. Well we can discuss, but we'll be going off-topic.
Hey hey can you help me again, this time it's paper 5 june 2007 , if for example l is a quantity in cm with an uncertainty +- 0.4, so what happen to the uncertainty if they ask for l^2
Let's assume l is 10.2 (+- 0.4). When l is squared, we square the two extreme points and subtract them to get uncertainty in the l squared value.
10.2^2 = 104.04 and uncertainty = (10.2+0.4)^2 - (10.2-0.4)^2
= 10.6^2 - 9.8^2
= 112.36 - 96.04 = 16.32
So, we have 104.04 (+- 16.32).
Hope you get it.
26 is easy.here a minima is formed that means distance between adjacent nodes or distance between adjacent antinodes is lambda/2http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w10_qp_12.pdf
I know I have a lot of doubts.. will be really grateful for help
Q5, 8, 14, 22, 25, 26, 33, and, 34
Well Young modulus is the same so extension would be sameQ25- Umm i guess extension will be the same as it obeys hookes law. Not sure though :/
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