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You'r Welcome!Thankyou guys :') I figured it out too
But thanks alot
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You'r Welcome!Thankyou guys :') I figured it out too
But thanks alot
If i am not wrong you have posted in the wrong section/thread. This is for AS And A Level.can someone please explain the bird question and the turbine question. (question 2 and question 3) please reply ASAP
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Physics (0625)/0625_s12_qp_32.pdf
There are two formulas for power that involve resistance,Ok so A simple question..
Why would Power be zero when resistance would be O or also infinity?
Why would power be zero in both the cases? :/
hey, Can I have an an explanation to question 7 all P23 2010
The answer in the MS said (ii) F=E.g
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w10_qp_23.pdf
here is the ms
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w10_ms_23.pdf
thank you
How did you attach the picture?Guys can someone help me here?
This question is from W13 physics 42.
Regarding the ADC 4bit question, how do I continue the table for the next five samples? How do I convert the voltage values into binary digits or bits?
you basically just divide continuously by 2 ...i.e. 0.25 ms is 10mv...10/2 give you 5,0...then 5/2 give you 2,1...and 2/2..gives you 1,0...so it would be 1010Guys can someone help me here?
This question is from W13 physics 42.
Regarding the ADC 4bit question, how do I continue the table for the next five samples? How do I convert the voltage values into binary digits or bits?
you basically just divide continuously by 2 ...i.e. 0.25 ms is 10mv...10/2 give you 5,0...then 5/2 give you 2,1...and 2/2..gives you 1,0...so it would be 1010
ill take a picture later on i dont think its clear in this explanation
Thnku!There are two formulas for power that involve resistance,
P = I^2*R (for series circuits, since current is constant). If resistance is 0 here, the power output is 0.
P = V^2/R (for parallel circuits, since voltage is constant). If resistance is infinite here, the power output is 0.
Question 3, part (c):
Wb q5 ?Question 3, part (c):
(i) The extension is proportional to the load (straight linear line on graph) (mass here, hence load), therefore yes, the spring obeys Hookes law.
(ii) F = kx.
Use any point on the line, for example (0.20, 27.5).
Since mass is on the x-axis and length on the y-axis, you need to change these to fit into the formula.
F = (0.20)(9.8) = 1.96 N.
x = extended length - original length = 27.5 - 20 = 7.5 * 10^-2 m.
Put these in the formula and you get,
k = 1.96/(7.5 * 10^-2) = 26.1 ~ 26 N/m.
(iii) Strain Energy = 1/2 * F * x
Force = (0.40)(9.8) = 3.92 N.
x = 35 - 20 = 15 * 10^-2 m.
Strain Energy = 0.5 * 3.92 * 15*10^-2 = 0.294 J.
Question 5:
tyQuestion 5:
(ii) The resistance of the wire to the point J is (0.9)*(4) = 3.6 ohms.
Potential difference = IR = (0.286)(3.6) = 1.03 V.
(iii) The value of E has to be the same as the potential difference across the wire XJ. To ensure that current is 0 (reverse polarities). Hence, 1.03 V.
(iv) Since there is no current passing through cell B, hence the internal resistance can be ignored (since potential difference will be 0 because 0 current).
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