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oh can u tell me which year is it from?Why does the ms say that there are less photons arriving per unit time?
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oh can u tell me which year is it from?Why does the ms say that there are less photons arriving per unit time?
no no, I'm talking about ppr 2 and all. for eg: if you are required to find the force and you are given m=5.0kg and a=1.2 m s^-2 then wont force=ma=6.0 N and not 6.00N?Yeah that too! but more significant number means less uncertainty...so 3 sf is much reliable. im talking about paper 4 here.
For paper 5, you're right!
no no, I'm talking about ppr 2 and all. for eg: if you are required to find the force and you are given m=5.0kg and a=1.2 m s^-2 then wont force=ma=6.0 N and not 6.00N?
paper 3 practical? i prefer using a cross since u circle a point which is anomalousIn paper 5 and 3, how do we plot the points?
Do we enclose points in a circle or use a cross?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w07_qp_4.pdf
Qn no. 5(b)ii.. Could someone please explain why 1cm^2 represents 156 microC?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w07_qp_4.pdf
Qn no. 5(b)ii.. Could someone please explain why 1cm^2 represents 156 microC?
How did you get 1.25 and 0.125? Sorry for bothering :/Just measure the area of the 1x1 square that u can form it comes out to be
1.25*0.125=0.15625mC = 156.25microC =156microC
This is just the area of one such box so multiply it with the no. of 1 x 1 squares below line to get answer !
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s11_qp_41.pdf Q 5(c) (i)any one some difficult questions pls. P4 :3
How did you get 1.25 and 0.125? Sorry for bothering :/
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s13_qp_43.pdfoh can u tell me which year is it from?
why you multiplied 0.39 twice ? :OI'm assuming that you got the answers for the previous two parts.. for part (iii),
Intensity received back= (intensity reflected at the muscle-bone boundary)e^-(23 * 4.1 * 10^-2)
[ e^-(23 * 4.1 * 10^-2) = 0.39]
intensity of the wave incident on the boundary was 0.39I, as calculated in part (ii)
0.33 of this was reflected at the boundary.
So intensity reflected at the muscle-bone boundary= .39 * .33I
answer= .39 * .33I * .39 = .050I
I hope this helps
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