Physics: Post your doubts here!

[Dr.MMM]

[quote="[/quote]
Please solve

 

[Wolfgangs]

http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_w02_qp_1.pdf
Q36

 

[ParulS]

[quote="

Please solve View attachment 45275[/quote]
The answer is B.

 

[umair1161]

mass = 800 * 1000
Work done = Energy
0.5 *m * v^2
0.5 * 800000 * 50^2 = 1 * 10^9

ahh! well done mate! thanks alot!!

 

[Hijab]

mass = 800 * 1000
Work done = Energy
0.5 *m * v^2
0.5 * 800000 * 50^2 = 1 * 10^9

Can u plz plz solve this question ... I would be grateful

 

[NabzJ]

[quote="

Please solve View attachment 45275[/quote]
As the micrometer measures the DIAMETER of the rod... you read the value of the micrometer to be 3.81 mm. to find the cross sectional area of the rod.. you have to divide 3.81 by 2 = 1.905 mm (radius) ... we know we can find the area of something using [(pi)x(r)^2] so the cross sectional area equals (pi x 1.905^2) which then equals 11.4 mm^2 which is B!

 

[ashcull14]

Can u plz plz solve this question ... I would be grateful

is it C?

 

[Rockstar RK]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w02_qp_1.pdf
Q36

is the answer a?

 

[Hijab]

is it C?

Yup

 

[ashcull14]

if its C then lambda/2=15*10^-3
so wvelenght=0.03m
f=3*10^8/0.03=1*10^10hz

 

[ZaqZainab]

Please solve View attachment 45275

The answer is B.[/quote]
It says the sectional area
If you read the value on the micrometer it is 3.81
so 3.81*0.5 is the radius
they want the crossectional area pie r^2
pie*(3.81*0.5)^2

 

[ashcull14]

yes

is the answer a?

 

[Rockstar RK]

yes

See its lengthy but easy...
All u shld know is that when the connection is in parallel, voltage division is the same for both..(here 2V in both)
Also resistors are equally distributed in the loops

 

[Dr.MMM]

A student uses a digital ammeter to measure a current. The reading of the ammeter is found to
fluctuate between 1.98 A and 2.02 A.

The manufacturer of the ammeter states that any reading has a systematic uncertainty of ± 1 %.

Which value of current should be quoted by the student?
A (2.00 ± 0.01) A
B (2.00 ± 0.02) A
C (2.00 ± 0.03) A
D (2.00 ± 0.04) A

How is the answer D?

 

[Laila39]

Anyone help me with Q.14, 32, 33, 35. Please.

 

[ashcull14]

can someone solve it ive forgotten hw i did it bfore

 

[Laila39]

2.02-1.98 = 0.04

 

[Rockstar RK]

yes

let the left loop be called as A and the right loop as B(loop of the resistors)
For loop A, total of resist. is 15ohm and in other loop i.e. B is also 15ohm
But both of them are in parallel that why resistance of the circit as a whole is 15/2 (1/15+1/15=2/15 and its inverse)

 

[Wolfgangs]

http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_w02_qp_1.pdf
q36 please

 

[Hijab]

if its C then lambda/2=15*10^-3
so wvelenght=0.03m
f=3*10^8/0.03=1*10^10hz

Why did u divide lambda by 2???