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We use A= -λN because we have Activity, Decay constant and N( the no of particles that are present).View attachment 61806
Can any1 pls xplain (b)?
y do we use A= -λN?
cuz N gives us undecayed nuclei nt amnt in atmosphere?
We use A= -λN because we have Activity, Decay constant and N( the no of particles that are present).
Using that formula we get N= 9.52 x 10^7 of Radon-222 atoms
So the ratio will be (2.52 ×10^25)/(9.52 x 10^7) giving 2.6 x 10^17. I believe this is the correct answer.
In 1m^3 of atmospheric air 9.52 x 10^7 atoms of Radon-222 are presentbt isn't N the no. of particles present in the sample n not in the air? Lyk the undecayed amnt?
I am an Engineering student. Got AAB in Phy, Math, and Chem respectively.Specifically looking for a candidate who appeared in A level exams and received an A and had Physics Chemistry and Biology just wanted few advices regarding how to approach the examintions and how to revise having 40 days in hand
(918 - 900) x 1000 = 18000yes but how?
Here is the solution to this question. I hope it helps.View attachment 61858
Anweris C .I didnt get how to solve it .please help me.
Can anyone explain these questions
View attachment 61855 Anwer is D
View attachment 61856 Answer is C how?
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