You are not including when both times the score will be 2.
Make sure that when you add the probabilties the total be 1.
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Statistics S1 post your doubts here
- Thread starter IGCSE13
- Start date
Make sure that when you add the probabilties the total be 1.
- Messages
- 19
- Reaction score
- 36
- Points
- 3
by which formula u got this result ? why its not LQ=520 and UQ = 690 ?
0.1056 are tall so rest are short and medium. Medium are twice as short so divide it into 3 groups, one is of short and other two are of medium.
Subtract the probability from 1 and apply the negative sign and take the z from the normal distribution function table.
- Messages
- 375
- Reaction score
- 226
- Points
- 53
general formula for Quartiles Q1 Q2 and Q3 ?
Q3 is 3/4 out of total measurement of wind speed...
thus, P(X<Q3)=0.75
- Messages
- 219
- Reaction score
- 228
- Points
- 53
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w09_qp_62.pdf q1 ii how do v find the z value????
- Messages
- 91
- Reaction score
- 70
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- 28
See for the first part they r saying should be female or watches Kops or both this means tht all female including any person if he/she watches Kops. So all female wich r 18 and 13 males who watch kops. So 25/30
For the second part probability of male is 18/30 and probability for person watches Kops is 16/30 so 18/30×16/30=8/25 and
P (Male n watches Kops) is 13/18 so both probabilities aren't equal so they are not independent
Probability not female and does not watch ‘Kops are Kids’: 5/30 (males who do not watch)
1- this probabilty and you get the answer.
- Messages
- 375
- Reaction score
- 226
- Points
- 53
- Messages
- 219
- Reaction score
- 228
- Points
- 53
Find the median or the Q2 by finding the mid-value of the data. Delete it and divide the rest of vaules into two parts. Find the median of these parts, the lower one will be Q1 or the lower quartile and the upper one will be Q3 or the upper quartile.
If the number of vaules is odd then the median or quartile will be a value included in the data and if the total number is even then the median or quartile will be between the mid values.
- Messages
- 354
- Reaction score
- 529
- Points
- 103
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w11_ms_62.pdf
Q4 (i) who 40~50 and not <50 only please help !
Q4 (i) who 40~50 and not <50 only please help !
- Messages
- 87
- Reaction score
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Anyone please ??
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w13_qp_62.pdf
QUESTION 6 here ^ part (iii) and (iv)
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w13_ms_62.pdf
I solved part (iii) this way
8P4*7!/2!*2! because there are 8 spaces for the 4letters
and part (iv) they are choosing 4 letters without Rs and Ms so 7 letters are left
they want at least 2 Es so i solved it this way ( 7C2+7C1)
PLEASE ITS URGENT !! can someone explain me what is my mistake ???
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w13_qp_62.pdf
QUESTION 6 here ^ part (iii) and (iv)
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w13_ms_62.pdf
I solved part (iii) this way
8P4*7!/2!*2! because there are 8 spaces for the 4letters
and part (iv) they are choosing 4 letters without Rs and Ms so 7 letters are left
they want at least 2 Es so i solved it this way ( 7C2+7C1)
PLEASE ITS URGENT !! can someone explain me what is my mistake ???
The interval is asked so it will be within 45-50 and not anywhere below 50
- Messages
- 19
- Reaction score
- 36
- Points
- 3
thnks i understood this step
= (1 – 0.1056)/3
= 0.2981
but how we got z=-0.53 by table ?can u explain pls
Subtract 0.2981 from 1
- Messages
- 87
- Reaction score
- 180
- Points
- 18
Kamihus can you help me please ???
I posted my doubt up in the thread
I posted my doubt up in the thread
You are finding the probability where all are separated but we have to find where all are not together. This can be done: All possible - All vowels together
For together: 8! × 4/2!2!=40320
Subtract this from the total ways.
7C2 or 7C1 cannot be used as 2 or 3 E's are already chosen so remaing are 4 not 7.
When 2 are chosen, it will be 4C2 for remaining are 4C1 when all 3 E's are chosen.