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View attachment 63816
View attachment 63817
can anyone pls explain me how to solve these two questions
First question was explained in #17975
For the 2nd question,
moles of ethanol = 2.3/46 = 0.05 mol
moles of ethanoic acid expected = 0.05 mol
mass of ethanoic acid expected = 3 g
actual mass obtained = 60% x 3 g = 1.8 g

