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No because then the particle would be moving AWAY from the field so repulsive force will become weaker.cant da answer be A ?
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No because then the particle would be moving AWAY from the field so repulsive force will become weaker.cant da answer be A ?
no am talking abt da amplitude question...No because then the particle would be moving AWAY from the field so repulsive force will become weaker.
XPFMember Q 17?http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_ms_12.pdf
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_12.pdf
any1 there???? i need help hereee ppl
Q no 17, 26 and 31........
Resistance in 1 wire of 800m = .005 * 800 = 4 ohmsno am talking abt da amplitude question...
can u plz solve dis one too?
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w10_qp_11.pdf
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w10_ms_11.pdf
Q no 34...ans is C
thank u soo much !!Resistance in 1 wire of 800m = .005 * 800 = 4 ohms
resistance in 2 wires = 4 ohms * 2 = 8 ohms
V = IR = 0.6 * 8 = 4.8 V
Min voltage = 16 + 4.8 = 20.8 V
XPFMember Q 17?
:$
i think i got thisXPFMember Q 17?
:$
Perpendicular =80/2 =40 mm
Find the angle.
Sin Θ = 40/50= 53.1°
As there are two tensions both equal, so Force = 2(cos 53.1 x 4) = Answer
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w10_qp_11.pdf
Q no 37 da answer is A but how is it A :S plz help
Erm. I don't think so.isn't the angle 45 anways? because if you draw parallegram of forces that is what i get
Ohh okay, thanks!Perpendicular =80/2 =40 mm
Find the angle.
Sin Θ = 40/50= 53.1°
As there are two tensions both equal, so Force = 2(cos 53.1 x 4) = Answer
Q no 5.... ans is D :/
View attachment 13046 it is a square with pythogrean triples 30,40,50 how can't it be 45??
at first i got 53.1 but the answer kept coming out wrong :S
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