Chem 11

[XPFMember]

ThankU and bst ov luk 2 u as well my p3 for chem is tday any idea whats coming

That's not allowed on the forum..(asking about what's coming) so better be careful..!

 

[raiyanfarrukh]

th calculation one or there was one questio like combustion and formation or combustion like that which one?
and yeah ofcourse ionization will be plus as energy REQUIRED to remove electron

the calculation one!!

 

[iceman]

HARD

wajahat our variant was 12 ...not 11

 

[Jaf]

^LOL xD

 

[1357913579]

the calculation one!!

actually i dont remeber whether it was - or + as for as i remeber what ever answer i got i worte that like you had to do 3 times combustion of carbon and 3 times combustion of hydrogen and all that is equal to i think combustion of ethanal or whatever that was + the formation valuse we had to find then you make thr formation value as the subject youll get the answer i just wrote that dirsctly i dont remember whether that was - or + you did same right??

 

[Thampi4]

seriously ???? ionisation energy is endothermic so it must be +

YES IONIZATION IS AN ENDOTHERMIC REACTION CUZ U R PUTTING IN ENERGY TO REMOVE THE ELECTRON.

 

[raiyanfarrukh]

actually i dont remeber whether it was - or + as for as i remeber what ever answer i got i worte that like you had to do 3 times combustion of carbon and 3 times combustion of hydrogen and all that is equal to i think combustion of ethanal or whatever that was + the formation valuse we had to find then you make thr formation value as the subject youll get the answer i just wrote that dirsctly i dont remember whether that was - or + you did same right??

i just used that values not multiplying with the factor 3 and using the formula for formation=products-reactants

 

[Thampi4]

can i ask what u guys got for the conditions for a gas to be ideal

and the equilibrium equation pls

 

[1357913579]

i just used that values not multiplying with the factor 3 and using the formula for formation=products-reactants

but when yo u balance the equation werent there 3 carbon and ydrogen cumbustion how can there be one carbon and hydrogen combustion

 

[1357913579]

i just used that values not multiplying with the factor 3 and using the formula for formation=products-reactants

i dont even rember soory it was 3 or 2 but i remember there i multiplied it not like how you did because there was option of 2 only i rember like 2 values where same in the 4 choices only the sign was different in the same values

 

[1357913579]

-1105 because it was enthalpy change of formation is always negative

iam not sure whether it was negative or positive but i remeber i had same answer as yours 1105 but my sign would have been negative as well if yours right because obviously because you dont change sign after calculation its like you get it by calculation

 

[user]

can i ask what u guys got for the conditions for a gas to be ideal

and the equilibrium equation pls

high temp and low pressure

2P <-> 2Q + R

 

[1357913579]

high temp and low pressure

2P <-> 2Q + R

i forgot the equilibrium which did they say has x moles and wich 2 all that?

 

[Thampi4]

i forgot the equilibrium which did they say has x moles and wich 2 all that?

q has 2moles at the beginning and r has x moles in equlibrium

 

[user]

i forgot the equilibrium which did they say has x moles and wich 2 all that?

q has 2moles at the beginning and r has x moles in equlibrium

and at eqbm. the total moles were 2 + x

 

[raiyanfarrukh]

high temp and low pressure

2P <-> 2Q + R

this was option b ryt?

 

[user]

this was option b ryt?

yeah as far as i remember..it was B

 

[raiyanfarrukh]

y

yeah as far as i remember..it was B

yeahhhhh

 

[Farah1996]

Are you guys tawkin about var 1 or 2??

 

[Ashique]

It should have been -254, right?