etcetraetcetra said:Please tell me what was the empirical formula was it C1.5 H3 O and molecular mass was 74 so the molecular mass was double of that right? please say yes :?
well i think molecular formula should never be in decimals like C1.5 H3 O... So i multiplied the equation bt 2 and got C3H6O2... and this was the same as used further with MR 74...