- Messages
- 1,558
- Reaction score
- 2,428
- Points
- 273
Sorry, could you elaborate that one?Hey guys/gals, i just figured out that the cell potential of a viable reaction must be positive... did u know that? I didnt.. that's news to me
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
Sorry, could you elaborate that one?Hey guys/gals, i just figured out that the cell potential of a viable reaction must be positive... did u know that? I didnt.. that's news to me
Umm.. i was just reading that chem guide site... it said that the cell potential of a viable reaction must be positive. you know how we calculate the overall cell potential when two half equations are given yeah? Yeah, that's basically supposed to be positive if we want to prove that the reaction does take place...if u dont get it, do u want me to post the link? It's an important point... u might wanna c it for yourselfSorry, could you elaborate that one?
Umm.. i was just reading that chem guide site... it said that the cell potential of a viable reaction must be positive. you know how we calculate the overall cell potential when two half equations are given yeah? Yeah, that's basically supposed to be positive if we want to prove that the reaction does take place...if u dont get it, do u want me to post the link? It's an important point... u might wanna c it for yourself
Oh right, thankyou so much. I realize it now that all my answers were positive. But instead of using the expression E(right) - E(left) for cell potential, I always use E(reduced) - E(oxidized).
Ahh.. u work the complicated way I use simple englishOh right, thankyou so much. I realize it now that all my answers were positive. But instead of using the expression E(right) - E(left) for cell potential, I always use E(reduced) - E(oxidized).
First time to know that ! Jazaki Allah khairan!!Oh right, thankyou so much. I realize it now that all my answers were positive. But instead of using the expression E(right) - E(left) for cell potential, I always use E(reduced) - E(oxidized).
Ahh.. u work the complicated way I use simple english
Hey, thanks brother... can u explain that last line again please?For a half equation the sign will only change when the equation changes the other way round... and hope you know that the salt bridge is KCl... In your diagram the equation for sulphur is S + 2e -> S^-2 so you must find the potential of this if in the data booklet is the other way round then you change the sign...
Also know that you can increase the voltage by increasing the potential difference between 2 elements you choose....
btw, my book says that the salt bridge is "can be made from a strip of filter paper soaked in a satursted solution of potassium nitrate".. but i'm going to beleive u cz i heard my teacher say something similar to ur statement (i think).For a half equation the sign will only change when the equation changes the other way round... and hope you know that the salt bridge is KCl... In your diagram the equation for sulphur is S + 2e -> S^-2 so you must find the potential of this if in the data booklet is the other way round then you change the sign...
Also know that you can increase the voltage by increasing the potential difference between 2 elements you choose....
Hey, thanks brother... can u explain that last line again please?
And Gémeaux Ariel Robert here is saying the sign does change, u might wanna pay attention...
No no no. The sign does Not change! At least that is how I've been attempting my questions so far..And Gémeaux, Ariel Robert here is saying the sign does change, u might wanna pay attention...
It can be either. Both KCl and KNO3 are correct.btw, my book says that the salt bridge is "can be made from a strip of filter paper soaked in a satursted solution of potassium nitrate"..
btw, my book says that the salt bridge is "can be made from a strip of filter paper soaked in a satursted solution of potassium nitrate".. but i'm going to beleive u cz i heard my teacher say something similar to ur statement (i think).
Jazak Allahu Khair anyway (I think ur Muslim No offense if u arent)
Ooooooooohhh... got it! Thanks a lot!!! and please excuse me for being so annoying- i am wake for 20 hrs straight :/ and i was "smart" to drink coffee an hour ago so... anyway..Jazak Allah!if you took an element with a potential of +0.52 and another one with -0.04, The voltage will be +0.52-(-0.04) = 0.56V
And if you take the +0.52 again but take another one which will give more voltage like -0.44, the voltage now will be higher = 0.96V, this way you can increase the voltage of a cell...
I said this because there are question asking "how will you increase the voltage of a cell?"...
No no no. The sign does Not change! At least that is how I've been attempting my questions so far..
It can be either. Both KCl and KNO3 are correct.
LOL! It's so cool to watch thisThe sign does change, you check again...
Bro... why u challengin us? I BELIEVE YOU!!! Oh God.. never mind, it will......umm..change? yeah, it'll change:ok i have question for you
the potential for Ag^+1 + 1e -> Ag is +0.80
what's the potential for Ag -> Ag^+1 + 1e ?
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now