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Chemistry: Post your doubts here!

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Actually, KMnO4 is "Silently preferred" in A levels. Basically its stronger and agreed upon to be stronger by most books, so that is what is expected of you

similarly, LiAlBH4 is STRONGER, but NaBH4 is more COMMONLY USED. Select at your own choice.
 
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KMnO4 is a strong oxidising agent if I'm not mistaken, and K2Cr2O7 is a weak oxidising agent.
You can use K2Cr2O7 for mild oxidation of Alcohol to Aldehydes... Unless a reflux with heat is used, then even K2Cr2O7 can oxidise alcohols directly to carboxylic acids.
Really, i always thought there was no difference... do they mark it wrong or anything if we confuse the two in the exam?
 
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KMnO4 is a strong oxidising agent if I'm not mistaken, and K2Cr2O7 is a weak oxidising agent.
You can use K2Cr2O7 for mild oxidation of Alcohol to Aldehydes... Unless a reflux with heat is used, then even K2Cr2O7 can oxidise alcohols directly to carboxylic acids.

umm yeah that i sorta knew.. i was thinking .. like..Why is one stronger and the other not?..
 
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umm yeah that i sorta knew.. i was thinking .. like..Why is one stronger and the other not?..
Although the mechanism for strength of oxidising agent is not involved in the A2 syllabus at all, its basically left best to say that ones mechanism of action is simply superior in speed or efficiency then the others.
 
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Actually, KMnO4 is "Silently preferred" in A levels. Basically its stronger and agreed upon to be stronger by most books, so that is what is expected of you

similarly, LiAlBH4 is STRONGER, but NaBH4 is more COMMONLY USED. Select at your own choice.

But KMnO4 would just oxidize the Alcohol into the corresponding carboxylic acid... What if we want the aldehyde then?
 
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Although the mechanism for strength of oxidising agent is not involved in the A2 syllabus at all, its basically left best to say that ones mechanism of action is simply superior in speed or efficiency then the others.
What?:eek:
 
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Although the mechanism for strength of oxidising agent is not involved in the A2 syllabus at all, its basically left best to say that ones mechanism of action is simply superior in speed or efficiency then the others.
okie dokie
 
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But KMnO4 would just oxidize the Alcohol into the corresponding carboxylic acid... What if we want the aldehyde then?
Then you would heat it with a fractional distillation set-up, whereby the volative aldehyde would be evaporated and collected off in a seperate vessel.
 
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ok so what you basically say is that since you need to only slightly oxidize an alcohol to an aldehyde you need a weaker oxidizing agent?
because if its stronger like KMnO4 it'll oxidize it directly to carboxylic acid? right? did i get it right?

similarly if i use LiAlH4 it'll convert an acid to alcohol, while nabh4 will turn it into an aldehyde?
 
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ok so what you basically say is that since you need to only slightly oxidize an alcohol to an aldehyde you need a weaker oxidizing agent?
because if its stronger like KMnO4 it'll oxidize it directly to carboxylic acid? right? did i get it right?

similarly if i use LiAlH4 it'll convert an acid to alcohol, while nabh4 will turn it into an aldehyde?
Isn't it all about the oxidising agent (whatever it may be) being in excess?
 
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