Mathematics: Post your doubts here!

[whitecorp]

Help!
View attachment 15411

Here are the full detailed workings:





Hope this helps. Peace.

 

[whitecorp]

hey guys, i need help in mechanics m/j 10

question 6 the 2nd part, why the acceleration is -3 and different than the first part which was 6? why the tension wasn't included in the calculation of the second part?

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_41.pdf

For the second part, the string has slackened and hence there will be no more tension in it. Clearly, since A is part of the original connected system,
when T=0, its acceleration will also change accordingly.

Hope this helps. Peace.

 

[iKhaled]

For the second part, the string has slackened and hence there will be no more tension in it. Clearly, since A is part of the original connected system,
when T=0, its acceleration will also change accordingly.

Hope this helps. Peace.

y the string has slackened ?

 

[bamteck]

Please someone help me for no. 11 (iii) whitecorp

http://www.xtremepapers.com/papers/...AS Level/Mathematics (9709)/9709_s09_qp_1.pdf

 

[whitecorp]

y the string has slackened ?

The particle B is resting on the ground, hence as A moves forward, the string is no longer taut. You can try to visualize this to convince yourself.
Hope it helps. Peace.

 

[whitecorp]

Needs a helping hand!
View attachment 15481

I will help you sort out Q5 first:



Hope this helps. Peace.

 

[whitecorp]

Please someone help me for no. 11 (iii) whitecorp

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s09_qp_1.pdf

You can calculate the area under the line CD between x=2 and x=3 (which is a trapezium) and subtract from it the area under the curve y=x^3-6x^2+9x between x=2 and x=3 (you can do this through basic integration) to get your answer.

Hope this helps. Peace.

 

[bamteck]

You can calculate the area under the line CD between x=2 and x=3 (which is a trapezium) and subtract from it the area under the curve y=x^3-6x^2+9x between x=2 and x=3 (you can do this through basic integration) to get your answer.

Hope this helps. Peace.

Thann you very much ! I was confused

 

[Albert Einstein]

Kuld u help me wid zis

 

[hussamh10]

tan(pi- x) = -tanx so ans is -k.

tan(pi/2 - x) = reflection of tanx means the ans will be inverse. 1/k
it is better explained in book from pages 172-179 core maths by s.bostock and s.chandler see there for clear understanding. by means of graphs

Thanku very much

 

[hussamh10]

View attachment 15387

omg sorry instead of all the pi i drew change it to 1/2pi..my fauly sorry :$

i hope this will help u !

Thanx alot man

 

[hussamh10]

Kuld u help me wid zis

ia answer to first part 1122KW just asking?

 

[aloha]

can any1 plz show me how to solve |x-2| +|3x-1|=0 and plot the graph too.........plz ur help will be highly appreciated.....

 

[steel]

UGRNET !
how to integrate e^3x^2 ?

 

[steel]

HOW TO SOLVE ? URGENT

 

[Albert Einstein]

ia answer to first part 1122KW just asking?

Nopes its 58800 W

 

[Amy Bloom]

whitecorp
Indeed you're a boss! Thanks mate for everything.

 

[whitecorp]

can any1 plz show me how to solve |x-2| +|3x-1|=0 and plot the graph too.........plz ur help will be highly appreciated.....

You can take a look at this to get some inspiration:

http://www.whitegroupmaths.com/2012/05/understanding-matters-6.html

Hope it helps. Peace.

 

[whitecorp]

whitecorp
Indeed you're a boss! Thanks mate for everything.

No problem, am glad to be of assistance. Peace.

 

[whitecorp]

HOW TO SOLVE ? URGENT

Notice that the integral is basically of the form f"(x) * e^ f(x), which should simply reduce to e^f(x) +C. Note though certain adjustments must be made to the constants (ie f(x)=-3x^2, which yields f'(x)=-6x, where clearly within your problem the constant -6 is missing).

Hope this helps. Peace.