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find the range for which 8(o.6)>x+3 ....its from the revision in d4. the questions there eat u...literally...what ws the question again?
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find the range for which 8(o.6)>x+3 ....its from the revision in d4. the questions there eat u...literally...what ws the question again?
There's a 'to the power x' too -.-find the range for which 8(o.6)>x+3 ....its from the revision in d4. the questions there eat u...literally...
oh yeah... guess i miss typed it . i just drew a graph for y=x+3 seeking help from the previous reply to get the answerThere's a 'to the power x' too -.-
I would do the same.oh yeah... guess i miss typed it . i just drew a graph for y=x+3 seeking help from the previous reply to get the answer
Ya exactly...Doing Maths after Add Maths seems like I'm doing Kindergarten in Grade 11. Such a Huge change in difficulty level.
For the first time and for surely the LAST, Thank You CIE!
me and my friend who didnot do addmath were doing a paper together i was constantly applying addmath concepts and it made it look 10 times as easyDoing Maths after Add Maths seems like I'm doing Kindergarten in Grade 11. Such a Huge change in difficulty level.
For the first time and for surely the LAST, Thank You CIE!
Point's Proved I Guess!me and my friend who didnot do addmath were doing a paper together i was constantly applying addmath concepts and it made it look 10 times as easy
LOL25 ki power 3x-1 hai ya 25 ki power 3x thi aur uss mein say -1 horaha hai ..?
MustafaMotani bhai meray thora halka haath rakho itni working aik post mein karo gay tu kiski samajh aayegi
its in D4 appendixhahahaha // isy waja say tu yeh DP hai .. warna tu kabki change kardi hoti
btw thanks for the center of rotation I didn't knew! actually which book has that chapter of transformations ? I couldn't find it in any of them ...
Soor I misunderstood the question ... I had to go at that time so I didnt read ur that post ..To be frank, i didnt understand the method u used..
then prac alot for such questions...aise sawal ai to i ll go blank in the paperssssss!!!
SorrY i didnt respond I was not hereHelp plzzz.... I'm doing this question on graphs . The graph is of the equation y=8(0.6)^x. The part i cant solve is find the solution of the equation 8(0.60)^x=x
how on earth can u solve that??? syed1995 ,@ashiqbal ,Dukeofwin MustafaMotani ... anyone??
anyone plz explain answer of q6 part (a).....Attached Files:
4024_w04_qp_2.pdf
File size:92.5 KB
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yeah it is necessaryis it necessary to memorize all those transformation matrices ?? is there no concept involved :\
yep ...i guess so!!135 ?
yup u are right.. It would be a great help if u tell me the method.. Thank u..Sarah22 we had to find distance of AB from top
I thought we had to find AB
IT would be 9 - 9cos 70 = 5.92
am I rite now.. ??
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