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That's what i got 7.777777778=7.78m/s
Mine was too like dat.......i just used da formula s=d/t n then use da values of the point c.......from where the decleration started! Ryt! Wat abot u guyz!
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That's what i got 7.777777778=7.78m/s
No guyz it was on b ! well wat made u consider itz place as A!what abt the LDR position? anybody who had time to use their brains in the last Q? :/
Well actuallt this question was based on formula of pressure......n it too simple.......luk......if da area ix bigger so there ix less pressure but more force to move it n itz like dat force ix inversly proportional to pressure! Meanz that if larger area so, less pressure but more force needed but if smaller area so less force but larger pressure.....! Ryt!hi! it ws fyn, alhamdulillah!
da one which moved a small dist is b'coz da area ws big. da other one coz da area ws small
Lol i'm not tooo worried. I mean I know I did good.Arent u people getting too sentimental over yuor answers? LOL! Forget it guys..Guess what I screwed up p3 and p1 but i am still not upset cox I know the GT is gonna be low Learn to learn from your mistakes
Are you so desperate to make yourself believe that you didn't lose those 5 marks that you will start insulting me?conduction is only fast in metals, it was glass. ur answers prove that u know nothing about physics u just memorize
i got 9.33 m/sguyz what was the max speed? :\
was it 7. something???
please discuss the paper !!
no the LDR should be in B!I wrote that too!
Did u take the distance as the steep line's height or something?
Coz for the speed we had to directly choose values from the graph of the distance and time..
yeahthe direction of the current was to the right?
i choose from the graph there was the higest 10m/sI wrote that too!
Did u take the distance as the steep line's height or something?
Coz for the speed we had to directly choose values from the graph of the distance and time..
dat ws 2.4V, i guesswat u wrote for the voltage between x and Y?
plz can u check my answer in this question: q5 biv http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Chemistry (0620)/0620_w10_qp_31.pdf.....dat ws 2.4V, i guess
At first i got 1.8 ohms as the resistance but then that is the total resistance of the circuit what i did was get the total resistance and the resistance of the parellel resistors then subtract both and i got a 1.1 ohms .
yes, dats da xplanation, but i ws too lazy 2 typ all datWell actuallt this question was based on formula of pressure......n it too simple.......luk......if da area ix bigger so there ix less pressure but more force to move it n itz like dat force ix inversly proportional to pressure! Meanz that if larger area so, less pressure but more force needed but if smaller area so less force but larger pressure.....! Ryt!
yupp!i choose from the graph there was the higest 10m/s
yes, dats ryt. u've got it.plz can u check my answer in this question: q5 biv http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Chemistry (0620)/0620_w10_qp_31.pdf.....
I thnk the ans is 1.8 ohms since voltage across R resistor is 3.6 v and total current is 2A then the resistance will be 3.6/2=1.8 ohmsthats the pefect answer for sure!
thank u!!yes, dats ryt. u've got it.
yes, dats ryt.I thnk the ans is 1.8 ohms since voltage across R resistor is 3.6 v and total current is 2A then the resistance will be 3.6/2=1.8 ohms
dnt mention it.thank u!!
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