Physics: Post your doubts here!

[omaaaar]

http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_s09_qp_2.pdf
Q7 full question don't understand how to do

 

[robinhoodmustafa]

usama321
Now check this question. It ask to draw a wave with PD of 60. and on x axis they have listed 1,2,3 etc so how do i know where angle 60 lies.

I understood the 180 PD one you told me earlier (Half the 360 one and start from there forward)

 

[ZaqZainab]

usama321
Now check this question. It ask to draw a wave with PD of 60. and on x axis they have listed 1,2,3 etc so how do i know where angle 60 lies.

I understood the 180 PD one you told me earlier (Half the 360 one and start from there forward)

View attachment 42228

360-3
60-0.5

 

[robinhoodmustafa]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_qp_2.pdf
Q7 full question don't understand how to do

First Part.
Resistance in Series : R+R...
Resistance in parallel : 1/R +1/R...


Second part.

Kirchhoff law.
Follow the Current direction and remember current divides in parallel and remain same in Series.
when is given part just focus on the direction he gives like " E2, I1 ,I2 and BCXYB part , forget about the other parts of the circuit like BYZA this way it would be easy to write down equation.
and read a bit about Kirchhoff from Book. It really helps

 

[robinhoodmustafa]

360-3
60-0.5

So a single complete wave.. only one wave end on 3 so it complete it on 360? and the complete(till 6) covers 720 degree??
and 60 how'd you find 60?

 

[ZaqZainab]

So a single complete wave.. only one wave end on 3 so it complete it on 360? and the complete(till 6) covers 720 degree??
and 60 how'd you find 60?

till 6 would be 2 waves and it would be 720
IF 360 is 3
then 60 is 0.5
cross multiply
3*60 /360

 

[DeViL gURl B)]

http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_s06_qp_2.pdf

Question 6
(C) please explain in detail ..

 

[ZaqZainab]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s13_qp_21.pdf
Q3bii
i found v using v^2=u^2 +2as and then found the k.e using 1/2 mv^2 it was the same answer as ms but not the way would i get all the marks?

 

[robinhoodmustafa]

till 6 would be 2 waves and it would be 720
IF 360 is 3
then 60 is 0.5
cross multiply
3*60 /360

Thaaaankyou JazakAllah

 

[Haya Ahmed]

What is the difference between slit separation and slit width and can Someone explain Q5 (c) here in this paper
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w07_qp_2.pdf
Thanks ! ^_^

 

[robinhoodmustafa]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s06_qp_2.pdf

Question 6
(C) please explain in detail ..

End Correction.
Antinodes are formed liltle above the test tube so

Node to Antinode is λ /4 so you have the wavelength calculated from part B (0.648)
so insert the lamda and divide by 4.

You will get 16.2 (distance from node to antinode.. and test tube length is 15.7 so antinode is formed 0.5 (16.2-15.7) above the tube.

edit:
The wave i drew would be 2nd overtone. I mistakenly drew 1st overtone as it clearly says loud noise.

 

[ZaqZainab]

What is the difference between slit separation and slit width and can Someone explain Q5 (c) here in this paper
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w07_ms_2.pdf
Thanks ! ^_^

5c(i) width is increasing means x us increasing more light is allowed to enter and so brighter fringes brighter
(ii) slit separation increases which is a in the eqation x=landa*D/a
so if a increases x decreases x is the fringe width

 

[usama321]

usama321
Now check this question. It ask to draw a wave with PD of 60. and on x axis they have listed 1,2,3 etc so how do i know where angle 60 lies.

I understood the 180 PD one you told me earlier (Half the 360 one and start from there forward)

View attachment 42228

Make sure you lag it behind baqi samajh aa gai hai to lag behind ka scene pata hai na?

 

[DeViL gURl B)]

End Correction.
Antinodes are formed liltle above the test tube so

Node to Antinode is λ /4 so you have the wavelength calculated from part B (0.648)
so insert the lamda and divide by 4.

You will get 16.2 (distance from node to antinode.. and test tube length is 15.7 so antinode is formed 0.5 (16.2-15.7) above the tube.

edit:
The wave i drew would be 2nd overtone. I mistakenly drew 1st overtone as it clearly says loud noise.
View attachment 42241

Thank you so much!!

 

[DeViL gURl B)]

Guys .. What do u mean by lamp shortening? Or lamp shortened? :$

 

[Mohammed salik]

Guys .. What do u mean by lamp shortening? Or lamp shortened? :$

Short Circuited. Means Current Doesn't Pass through The lamp.. It passes through an alternative Path which has Lower Resistance.!
Hope this is what u Meant !

 

[DeViL gURl B)]

Ye

Short Circuited. Means Current Doesn't Pass through The lamp.. It passes through an alternative Path which has Lower Resistance.!
Hope this is what u Meant !

yes and thank u!!!!

 

[DeViL gURl B)]

Guys what do u mean by .. Slit separation and slit width?
As in what happens to the fringes by each of them ? .. Like brightness and the X ?
Hope u guys get what in askin !
Please help
Thank u

 

[Mohammed salik]

5c(i) width is increase means x us increase more light is allowed to enter ans so brighter fringes brighter
(ii) slit separation increases which is a in the eqation x=landa*D/a
so if a increases x decreases x is the fringe width

Guys what do u mean by .. Slit separation and slit width?
As in what happens to the fringes by each of them ? .. Like brightness and the X ?
Hope u guys get what in askin !
Please help
Thank u

Loot At the Figure Attached Above..!
Answered By ZaqZainab! Post #8586

 

[DeViL gURl B)]

Loot At the Figure Attached Above..!
Answered By ZaqZainab! Post #8586

Thank u ! And ZaqZainab
Okhay if u don't mind can I ask one more doubt ? Please