PlanetMaster
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It says decreases to 94%!wont
wont we subtract 0.94 from 1D as it says DECREASED BY 94%
If it were decreases by 94%, then we would subtract 0.94 from 1.
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It says decreases to 94%!wont
wont we subtract 0.94 from 1D as it says DECREASED BY 94%
You need to take intersections of both waves where they are going in the same direction.View attachment 70518
CAN SOMEONE EXPLAIN THIS QUESTION?
During one oscillation, point A moves a distance of 80mm as given in the question.View attachment 70537
AND THIS QUESTION AS WELL THANKYOU. HOW WILL WE FIND THE AMPLITUDE IN THIS QUESTION?
You need to take intersections of both waves where they are going in the same direction.
From the graph, these can be either 0 to 0.5 or it can be 0.5 to 0.8.
We can then use ratios to calculate the phase difference
[imath]\frac{\Delta t}{T} = \frac{\Delta \phi}{360^{\circ}}[/imath]
Since T is 0.8 i.e one full cycle, using [imath]\Delta t = 0.3[/imath] gives us [imath]\Delta \phi = 135^{\circ}[/imath] and using [imath]\Delta t = 0.5[/imath] gives us [imath]\Delta \phi = 225^{\circ}[/imath]
So the answer is C i.e 135 which is also 360-225 i.e. 13
Hey redox233, I am not sure if you still need help on this, but let me explain this to you:-PlanetMaster can u pls explain this uestion? thankyou!
No worries pal. For both waves, we can take the points they intersect 0 displacement in the same direction.
Like this:View attachment 70545
A)a child of mass 35 kg movies down a sloping path on a skate board. the sloping path makes an angle 45 degree with the horizontal. the constant speed of the child along the path is 6.5 m/s. Calculate:
a) vertical dist through which child moves in 1.0s (done)
b) the rate at which potential energy is being lost (g=9.81 m/s^2) (confusion)
How is the answer to b) 80 J/s??
All I did was P = (35x9.81x0.51)/1 which gives answer 175 J/s (or 175 W)
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