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MJ 2010 42 Q1
2R above earth's surface ---->3R from the centre of the earth.
So, potential at 3R from center of the earth = 2.1 * 10^7 J/kg
v knw tht change in kinetic energy = change in potential energy
so, 1/2 * m * v^2 = mgh ----> φ * m
1/2 v^2 = φ
v^2 = (2.1 * 10^7) * 2
v = 6.5 * 10^3 m/s
Hope u gt it!