Physics: Post your doubts here!

[sma786]

a (i) So we know that the horizontal component is 8.2ms-1 since there the horizontal component never changes.
So Vcos60=8.2 (V is the Resultant velocity)
V=16.4ms-1
So, U know that vertical component =Vsin@
16.4sin60=14.2ms-1
ii) Since we are dealing with the vertical height here we will use the VERTICAL component of velocity.
So, initially u can see that vertical component of velocity=0
So v^2=u^2+2gh
(14.2)^2=2(9.81)h
h=10.3.
iii)This one is simple.U have to know the concept that the horizontal component of velocity remains constant.So the distance x u can easily get by multiplying the time taken with the horizontal component of velocity.So U find time like this:
V=u+gt
14.2=0+9.81t
t=1.4475s
X =v x t
X=8.2 x 1.4475
X=11.87m.
I hope u understood this question.If u have any problem i will try my best to respond.
Welcum.

Thankyou so much!! <3

 

[Haya Ahmed]

You guys confuse me
what i did was just made a line continue the wind line but with a little less angle

Nope I think mine is right cuz I got the ans with it !

 

[ZaqZainab]

Nope I think mine is right cuz I got the ans with it !

i am not saying that you are wrong but i don't understand the way you are going it

 

[Princess Raven]

in 1/4 cycle antinode gets from highest point to zero. then in 1/4 it gets to lowest point then in 1/4 it gets to zero. then in 1/4 it gets back to max. so in one T it completes on cycle.


here is Suchal explanation
https://www.xtremepapers.com/commun...st-your-doubts-here.9860/page-440#post-782703
Physics: Post your doubts here!

OMG thank u! Understand it perfectly now okay so if we calculated time
Period and say it was 2/4 not 1/4 we would just draw the exact same thing right but since it's 1/4 we draw a horizontal line

 

[unique111]

OMG thank u! Understand it perfectly now okay so if we calculated time
Period and say it was 2/4 not 1/4 we would just draw the exact same thing right but since it's 1/4 we draw a horizontal line

Since, 5 ms is 1/4th of total T, we draw a straight line?

 

[DeViL gURl B)]

Thanks! But how do we get the no. Of maxima & minima?

Maxima is the bright fringes and minima is the dark. Thus, u can count.

 

[DeViL gURl B)]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w13_qp_21.pdf

Thought blocker question no 5 a (ii) 1. How do u find the amplitude?
Please help
Thank u

 

[viruses]

what are up and down quarks???????

 

[Thought blocker]

They are saying that point A moves 80mm. Point A is a point on the rope and it is not moving sideways but only moving up and down.
So it moves 80mm first going up to amplitude then it goes back to equilibrium position back down to a trough and back up so the actual amplitude is 80/4=20.

Hope this help u DeViL gURl B)

 

[Haya Ahmed]

How to find the pressure under 10 meters depth of water ?! and are we supposed to ad atmoshperic pressure and how much is atm pressure ?! ... Please some one answer ASAP


Suchal Riaz
ZaqZainab
Thought blocker

 

[Thought blocker]

How to find the pressure under 10 meters depth of water ?! and are we supposed to ad atmoshperic pressure and how much is atm pressure ?! ... Please some one answer ASAP


Suchal Riaz
ZaqZainab
Thought blocker

GImme the paper link please.

 

[Haya Ahmed]

GImme the paper link please.

It came once in M/J 2002 not in Xtreme Papers .. you'll have to go for www.freeexampapers.net

 

[Thought blocker]

It came once in M/J 2002 not in Xtreme Papers .. you'll have to go for www.freeexampapers.net

Link not avilable :/

 

[Princess Raven]

Yup

Since, 5 ms is 1/4th of total T, we draw a straight line?

since the wave is already at 1/4 now by adding 1/4 it becomes 2/4 so it's a horizontal line

 

[Usman Chughtai]

http://papers.xtremepapers.com/CIE/...AS Level/Physics (9702)/9702_w09_qp_22.pdfCan anyone kindly do Q3 part b link attached ?

 

[Thought blocker]

Since, 5 ms is 1/4th of total T, we draw a straight line?

 

[Asif Bin Latif]

9702_w10_ms_21 ...........ques no.6 (b)i,ii,iii

 

[Ahmed Aqdam]

View attachment 42525

From where did you get the 20ms?

 

[Usman Chughtai]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w09_qp_22.pdfCan anyone kindly do Q3 part b link attached ?

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w09_qp_22.pdf

Sorry by mistake that was copied wrong its oct/nov 2009 Q3 part b .... have attached the correct link again

 

[Thought blocker]

From where do you get the 20ms?

20ms ?